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aivan3 [116]
3 years ago
8

One side of a rectangle is 3 inches shorter than the other side, and the perimeter is 54 inches. What are the dimensions

Mathematics
1 answer:
vodomira [7]3 years ago
8 0

Answer:

2(x-3)+2x=54

Step-by-step explanation:

Take the side length of the rectangle as x

For the perimeter we must have - as we also have 2 lots of a side that is 3 inches shorter than x.

2x + 2(x-3) = 54

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10=ax+bx solve for x <br> With steps please
laila [671]

Answer:

\displaystyle 10 = ax + bx \rightarrow x = \frac{10}{a + b}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Factoring

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle 10 = ax + bx

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Factor:                                                                                                               \displaystyle 10 = ax + bx \rightarrow 10 = x(a + b)
  2. [Division Property of Equality] Divide a + b on both sides:                           \displaystyle 10 = ax + bx \rightarrow x = \frac{10}{a + b}
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timama [110]

Answer:

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50=8x+2

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<em>plz mark me brainliest</em> ;)

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3 years ago
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