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matrenka [14]
2 years ago
7

Elisa puts $1,000 into each of 2 bank accounts. Account A: 3% interest rate, compounded annually, which is ✔ exponential growth

Account B: $40 bonus added to the account each year, which is ✔ linear growth How much money will be in Account A at the end of 3 years? $ How much money will be in Account B at the end of 3 years? $
Mathematics
1 answer:
Bas_tet [7]2 years ago
8 0

Answer:

Account A: 1,092.73

Account B: 1,120

Step-by-step explanation:

After 3 years, account B will yield more. But, in the long run the exponential function, which is account A, will make more money. I hope this helps :)

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Mike rides his motor cycle 18 miles in 1/2 hours what is his average speed in mph
SCORPION-xisa [38]
We know, Average speed = distance / time

So, s = 18 / 1/2

s = 18 * 2 / 1

s = 36 mph

In short, Your Answer would be: 36 mph

Hope this helps!
5 0
3 years ago
Read 2 more answers
assume that women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. find the
drek231 [11]

Answer:

65.3658 inches

Step-by-step explanation:

Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value x_{0} such that P(X < x_{0}) = 0.76, but, 0.76 = P(X < x_{0}) = P((X-63.6)/2.5 < (x_{0}-63.6)/2.5) = P(Z < (x_{0}-63.6)/2.5), i.e., (x_{0}-63.6)/2.5 is the 76th percentile of the standard normal distribution. So, (x_{0}-63.6)/2.5 = 0.7063, x_{0} =63.6+(2.5)(0.7063) = 65.3658. Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.

7 0
3 years ago
If the timer was started at the begining if the race would it affect the median. Why, not?
Ilia_Sergeevich [38]
Yeah It Would

~Hope This Helps :)
Need More Help With Question Just Inbox Me 
Also Rate, Give Thanks, And Mark As Brainiliest. 
Thank You ;) 
7 0
3 years ago
Solve the equation 3^(2x) -4*3^(x+1) + 27 = 0. use rules of exponents to change 3^(x+1)​
Leviafan [203]

Answer:

\huge\boxed{x=1\ \vee\ x=2}

Step-by-step explanation:

3^{2x}-4\cdot3^{x+1}+27=0\\\\\text{use}\ (a^n)^m=a^{nm}\ \text{and}\ a^n\cdot a^m=a^{n+m}\\\\\left(3^x\right)^2-4\cdot3^x\cdot3^1+27=0\\\\\left(3^x\right)^2-12\cdot3^x+27=0\\\\\text{substitute}\ 3^x=t>0\\\\t^2-12t+27=0\\\\t^2-3t-9t+27=0\\\\t(t-3)-9(t-3)=0\\\\(t-3)(t-9)+0\iff t-3=0\ \vee\ t-9=0\\\\t-3=0\qquad\text{add 3 to both sides}\\\boxed{t=3}\\\\t-9=0\qquad\text{add 9 to both sides}\\\boxed{t=9}

\text{We return to substitution:}\\\\3^x=t\\\\3^x=3\ \vee\ 3^x=9\\\\3^x=3^1\ \vee\ 3^x=3^2\\\\\boxed{x=1}\ \vee\ \boxed{x=2}

4 0
3 years ago
What is the most reasonable estimate for 54% of 168<br> <br> A:8.4<br> B:46<br> C:84<br> D:110
lianna [129]
Just by estimating, 54% is a little over 1/2 of 168.  You know by that, that neither A or B is close. The real answer is 90.72, so if your instructor wants you to round up, it would be D
8 0
3 years ago
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