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enot [183]
3 years ago
11

At a track meet, Jacob and Daniel complete in the 220 m hurdles. Daniel finishes in 3/4 of a minute. Jacob finishes with 5/12 of

a minute remaining. Who ran the race in the faster time.
Bonus: Express the difference in their times as a fraction of a minute.
Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
6 0
Well, 60(sec.) divided by 4 = 15. 15x3= 45 seconds is Daniel's time.
60 divided by 12 = 5. 5x5 = 25 seconds is Jacob's time. Jacob finished faster. Hope this helps!
Pavel [41]3 years ago
5 0

Jacob ran the race in the faster time

Further Explanation:

Daniel complete the hurdle at = 3/4 of a minute

Recall, 1 minute = 60 seconds

Therefore, Daniel complete the hurdle at 3/4 of 60 [secs]

= 3/4 x 60  

= 3 x 60 ÷ 4

= 180 ÷ 4

= 45 seconds

Jacob complete the hurdle with a remainder = 5/12 of a minute  

Recall, 1 minute = 60 seconds

Therefore, Jacob complete the hurdle with the remainder of 5/12 of 60 [secs]

= 5/12 x 60

= 5 x 60 ÷ 12

= 300 ÷ 12

= 25 seconds  

To find out how many minute Jacob used to complete the race:

60 seconds – 25 seconds=

= 35 seconds  

Since Daniel complete the race in 45 seconds, and Jacob complete the race in 35 seconds, in Athletics, the fastest of the two in completing the race is Jacob because, the time at which he complete the race is not greater than the time at which Daniel complete the race. And as such, the fastest of the two (Jacob) whose time is lesser is adjudged the winner of the race.

Deriving the difference in their times as a fraction of a minute:

The difference in their times is expressed as:

Daniel’s time [45 seconds] – Jacob’s time [35 seconds]

Therefore,

= 45 – 35

= 10 seconds  

Expressing the difference as a fraction of a minute:

Since 1 minute = 60 seconds

Hence, the fraction would be:

10/60

= 1/6

The given answers were derived as a result of the usage of Multiplication, Division and Subtraction, being functions of a number problem in mathematics.

LEARN MORE:

Track brainly.com/question/362542

KEYWORDS:

  • Seconds
  • Minute
  • Fraction
  • Difference
  • Time
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This Question: 1 pt
zhenek [66]

\huge{ \mathfrak{  \underline{ Answer }\:  \:  ✓ }}

Angles forming linear pair are :

\mathrm{\angle EFG  \:  \: and \:  \:   \angle GFH}

And we know, they are supplymentary

  • \mathrm{\angle EFG  \:   +  \:   \angle GFH}  = 180 \degree
  • 3n +1 9 \degree+ 2n + 36\degree = 180 \degree
  • 5n + 55\degree = 180\degree
  • 5n = 125\degree
  • n = 25\degree

So, the measures of the given angles are :

  • \mathrm{\angle EFG } = 3n + 19
  • \mathrm{ \angle EFG = (3  \times 25\degree)  + 19}
  • \mathrm{ \angle EFG = 75 \degree+ 19\degree}
  • \mathrm{ \angle EFG = 94\degree}

And

  • \mathrm{ \angle GFH = 2n + 36}
  • \mathrm{ \angle  GFH = (2 \times 25\degree) + 36\degree}
  • \mathrm{ \angle GFH = 50\degree + 36\degree}
  • \mathrm{ \angle GFH = 86\degree }

_____________________________

\mathrm{ ☠ \: TeeNForeveR \:☠ }

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