2 years ago

Please help meeeeeeeeeee!

Mathematics

1 answer:

aleksandr82 [10.1K]2 years ago

8 0

0.86602540378 is the sign of 60 degrees

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What basic trigonometric identity would you use to verify that sinx cosx tanx=1-cos^2x

andre [41]

Answer:

$sin^2x+cos^2x=1$ is used to prove the given equation.

Step-by-step explanation:

We have given an equation:

$sinx\cdot cosx\cdot tanx=1-cos^2x$

We will consider right hand side first

tan x can be written as:

$tanx=\frac{sinx}{cosx}$

So, on substituting tan x in the left hand side of the given equation we get:

$sinx\cdot cosx\cdot \frac{sinx}{cosx}$

Cancel common term from denominator and numerator which is cosx we get

$sin^2x$

And we have an identity:

$sin^2x+cos^2x=1$

$\Rightarrow sin^2x=1-cos^2x$

Hence, right hand side is equal to $sin^2x$ .

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2 years ago

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Marissa wants to babysit to earn some extra money. She already has $250 in her bank account. The equation f(x) = 22x + 250 can b

sineoko [7]

Answer:

22 represents how much she gets paid by the hour

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3 years ago

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Four students about to purchase concert tickets for $18.50 for each ticket discover that they may purchase a block of 5 tickets

soldier1979 [14.2K]

So, its 18.5 per person
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80/5=16
18.5-16=2.5

They would each save 2.5 dollars each.</span></span>

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2 years ago

The real numbers $x$ and $y$ are such that \begin{align*} x + y &= 4, \\ x^2 + y^2 &= 22, \\ x^4 &= y^4 - 176 \sqrt{

tamaranim1 [39]

You get everything you need from factoring the last expression:

$x^4-y^4=-176\sqrt7$

The left side is a difference of squares, and we get another difference of squares upon factoring. We end up with

$x^4-y^4=(x^2-y^2)(x^2+y^2)=(x-y)(x+y)(x^2+y^2)$

Plug in everything you know and solve for $x-y$ :

$-176\sqrt7=(x-y)\cdot4\cdot22\implies x-y=\boxed{-2\sqrt7}$

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3 years ago

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3k-2=10 whats the answer

kap26 [50]

Answer:

k = 4

Step-by-step explanation:

3k - 2 = 10

3k - 2 + 2 = 10 + 2 (adding 2 to both sides)

3k = 12

3k/3 = 12/3 (dividing both sides by 3)

k = 4

Happy to help :)

4 0

2 years ago