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mestny [16]
2 years ago
11

Which statement, if true, would help prove that quadrilateral

Mathematics
1 answer:
BigorU [14]2 years ago
4 0

Answer:

i believe its a

Step-by-step explanation:

.........

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This table gives the dimensions for a scale drawing of a house. Every 2 inches on the scale drawing represents 1.5 feet of the o
Damm [24]
It’s 3 inches in diameter
5 0
2 years ago
Read 2 more answers
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
Sunny_sXe [5.5K]

Answer:

<h2>\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }</h2>

First option is the correct option.

Step-by-step explanation:

\frac{2x + 5}{ {x}^{2} - 3x }  -  \frac{3x + 5}{ {x}^{3} - 9x }  -  \frac{x + 1}{ {x}^{2} - 9 }

Factor out X from the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x( {x}^{2}  - 9)}  -  \frac{x + 1}{ {x}^{2}  - 9}

Using {a}^{2}  -  {b}^{2}  = (a - b)(a + b) , factor the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x(x - 3)(x + 3) }  -  \frac{x + 1}{(x - 3)(x + 3)}

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}

Multiply the parentheses

\frac{2 {x}^{2}  + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}

Distribute -x through the parentheses

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 -  {x}^{2} - x }{x(x - 3)(x + 3)}

Using {a}^{2}  -  {b}^{2}  = (a + b)(a - b) , simplify the product

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 -  {x}^{2}  - x}{x( {x}^{2}  - 9)}

Collect like terms

\frac{ {x}^{2}  + 7x + 15 - 5}{x( {x}^{2}  - 9)}

Subtract the numbers

\frac{ {x}^{2}  + 7x + 10}{ x({x}^{2}   - 9)}

Distribute x through the parentheses

\frac{ {x}^{2}  + 7x + 10}{ {x}^{3}  - 9x}

Write 7x as a sum

\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }

Factor out X from the expression

\frac{x(x + 5) + 2x + 10}{ {x}^{3}  - 9x}

Factor out 2 from the expression

\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }

Factor out x + 5 from the expression

\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }

Hope this helps...

Best regards!!

6 0
2 years ago
Read 2 more answers
Quadrilateral ABDE is a rectangle. DE = 4 in. and BD = 6 in. If the rectangle is rotated about a line through CF, cylinder Y is
postnew [5]

Answer:

1 in. is the answer.

Step-by-step explanation:

Solution: A Rectangle ABDE in which DE=4 inches and BD= 6 inches

 There are two kinds of rotations

1. one along the Breadth, side having length 6 inches,i.e rotated along line GH,  Cylinder Z is created.

Radius of cylinder Z=6/2= 3 inches

2. Second along the Length, Side having length 4 inches,i.e rotated about a line CF, cylinder Y is created.

Radius of cylinder Y= 4/2= 2 inches

Difference in Radii= Radius of cylinder Z  -  Radius of cylinder Y

                              =  3 - 2= 1 inches

Diagram shown below of both the cases:

7 0
3 years ago
Read 2 more answers
At a sand and gravel plant, sand is falling off a conveyor and onto a conical pile at a rate of 10 cubic feet per minute. The di
lawyer [7]

Answer:

0.0063 ft / min

Step-by-step explanation:

From the problem statement we have that the variation in volume with respect to time is equal 10, like this:

dV / dt = 10 ft ^ 3 / min

We know that the volume of the cone is given by the equation:

V = (1/3) * Pi * r ^ 2 * h

Now, we are mentioned that the diameter of the base of the cone is approximately three times the altitude, therefore:

2r = 3h, solving for r we have:

r = (3/2) * h, replacing the volume equation:

V = (1/3) * Pi * [(3h / 2) ^ 2] * h, solving we have:

V = (3/4) * Pi * h ^ 3

They ask us to calculate the change in height with respect to time, that is dh / dt

Therefore we derive both sides with respect to time, we have to:

dV / dt = (3/4) * Pi [3 * (h ^ 2) dh / dt] = (9/4) * pi * (h ^ 2) * dh / dt

reorganizing for dh / dt, we have:

dh / dt = [4/9 * pi * (h ^ 2)] * dV / dt

Knowing that h is 15 and dV / dt is 10, we replace these values:

dh / dt = [4/9 * 3.14 * (15 ^ 2)] * 10 = 0.0063 ft / min

0.0063 ft / min would be the change in height with respect to time.

4 0
3 years ago
Suppose a triangle has sides a, b, and c and the angle opposite the side of length a is acute what must be true?
ANTONII [103]

The true statement about the triangle is (a) b^2 + c^2 > a^2

<h3>How to determine the true inequality?</h3>

The sides are given as:

a, b and c

The angle opposite of side length a is an acute angle

The above means that:

The side a is the longest side of the triangle.

The Pythagoras theorem states that:

a^2 = b^2 + c^2

Since the triangle is not a right triangle, and the angle opposite a is acute.

Then it means that the square of a is less than the sum of squares of other sides.

This gives

a^2 < b^2 + c^2

Rewrite as:

b^2 + c^2 > a^2

Hence, the true statement about the triangle is (a) b^2 + c^2 > a^2

Read more about triangles at:

brainly.com/question/2515964

#SPJ1

4 0
2 years ago
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