Answer:
5
Step-by-step explanation:
The sum of adjacent sides of the rectangle is half the perimeter, 50, so ...
... AH = 50-40 = 10
Then ...
... OP +QR = 10 = 2×OP . . . . . QR ≅ OP
... OP = 5 = PQ . . . . . . . . . . . . PQ ≅ OP
Answer:
b
Step-by-step explanation:
Answer:
m∠HMO=102°
Step-by-step explanation:
we know that
In a Rhombus the diagonals bisect the angles and opposite angles are equal
In this problem
Angles HMO and HTO are opposite angles
m∠HMO=m∠HTO
m∠HTM=(1/2)m∠HMO ----> because the diagonals bisect the angles and opposite angles are congruent
substitute the values

solve for x

<em>Find the measure of angle HMO</em>
m∠HMO=(12x-6)°
substitute the value of x
m∠HMO=(12(9)-6)=102°
see the attached figure to better understand the problem
Answer:
Step-by-step explanation:
x-30=14-3x
collect like terms: 4x=14+30
add numbers: 4x=44
divide both sides by 4
x=11
Answer:
in triangle ACD and BCE
AC = EC
angle ACD = angle ECB ( COMMON ANGLE).
CB = CD
BY side and side criteria
triangle ACD is congruent to triangle BCE
so angle a is congruent to angle E
hence, proved