<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
x= -4
Step-by-step explanation:
2x+4=6x+20
so 2x-6x=20-4
divide both sides by -4
-4x/-4 = 16/4
=-4
Answer:
Step-by-step explanation:
Since 40% of the crew are men, which means n. 40=8 n=8/. 40 n=20 total number of crew 20 - 8=12 are women
Easy. Just add a 0 on the end of the numerator and denomenator.
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