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3 years ago

I really need the answer to this question.

Mathematics

2 answers:

anzhelika [568]3 years ago

7 0

Answer:

True

Step-by-step explanation:

It's true because you are multiplying 3 four times

Phoenix [80]3 years ago

4 0

Answer:

True

Step-by-step explanation:

Exponents tell how many times the base number is multiplied to itself so exponent 4 means three multiplied by itself 4 times

3*3*3*3

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What is the slope of the line whose equation is -48 = 22 - Sy? Enter your answer in the box

Olenka [21]

What’s the problem?
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5 0

3 years ago

It allows us to express a very small or very large number in compact form, what is this.

lesya692 [45]

Scientific notation

Explanation:

…

4 0

2 years ago

If an object has a mass of 12Kg on Earth, what would its mass be on the Moon and Mars?

Leviafan [203]

Answer:

mars = 4.54 kg and moon = 1.98 kg

Step-by-step explanation:

12 kg on mars = 4.54 kg

12 kg on moon = 1.98 kg

6 0

3 years ago

Ahmed, Walid and Faisal made $1446 profit from selling used books. If Ahmed to receive double amount of Faisal and Walid to rece

sukhopar [10]

Answer:

Faisal will receive $ 241
Ahmed will receive $ 482
Walid will receive $ 723.

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Profit Ahmed, Walid and Faisal made from selling used books = $ 1,446

Ahmed to receive double amount of Faisal

Walid to receive triple amount of Faisal

2. How much does each one receive?

Let x to represent the amount Faisal to receive
Let 2x to represent the amount Ahmed to receive (double amount of Faisal)
Let 3x to represent the amount Walid to receive (triple amount of Faisal)

Therefore, we have:

x + 2x + 3x = 1,446

6x = 1,446

x = 1,446/6

x = 241 ⇒ 2x = 482 ⇒ 3x = 723

Faisal will receive $ 241, Ahmed will receive $ 482, and Walid will receive $ 723.

6 0

3 years ago

√48a^4 b^5 c^3 d simplify and keep it in radical form

Morgarella [4.7K]

I will assume the square root extends all the way across.

$\sqrt{48a^4b^5c^3}$

$\sqrt{2^4\cdot3\cdot a^4b^5c^3}$

$\sqrt{(2^2)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}$

$\sqrt{(4)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}$

$\sqrt{(4\cdot a^2 \cdot b^2 \cdot c)^2\cdot3\cdot b\cdot c}$

$4\cdot a^2\cdot b^2\cdot c\sqrt{3\cdot b\cdot c}$

$\boxed{4a^2b^2c\sqrt{3bc}}$

3 0

4 years ago