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alexandr1967 [171]
3 years ago
9

Anybody help me please

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
8 0

Answer:

The second one, I think.

GrogVix [38]3 years ago
7 0

Answer:

Rotation 180° counterclockwise about the origin

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The taylor series about x=5 for a certain function converges
ikadub [295]

The evaluation of the function f(x)=e^x at a=0 and x=5 by the taylor series will have a value 65.37.

<h3>What is taylor's series?</h3>

We know the fromula of taylor series is given as:

f(x)=f(a)+\dfrac{f'((a)}{1!}(x-a)+\dfrac{f''(a)}{2!}(x-a)^2+\dfrac{f'''(a)}{3!}(x-a)^3.................

Now for the function f(x)=e^x the taylor's series will become.

f(x)=e^a+e^ax+\dfrac{e^ax^2}{2!}+\dfrac{e^ax^3}{3!}+\dfrac{e^ax^4}{4!}

f(x)=1+x+\dfrac{x^2}{2!}+\dfrac{x^3}{3!}+\dfrac{x^4}{4!}

So at x=5 the values will become

f(x)=1+5+12.5+20.83+26.04=65.37

hence the evaluation of the function f(x)=e^x at a=0 and x=5 by the taylor series will have a value 65.37.

To know more about Taylor series follow

brainly.com/question/24188700

#SPj4

4 0
2 years ago
If a^1/n=r, then which of the following are true statements? Check all that apply.
posledela
1) no
2 yes
3) yes
4) no
4 0
3 years ago
3 Calculate the missing values <br>3:5 -&gt; 30 :<br><br>​
RoseWind [281]

Answer:

3:5 = 30:50 because it is ratio 3 x 10 = 30 5 x 10 = 50

4 0
3 years ago
Just asking even or odd multiplicity, help.
gladu [14]

if you want me to be real with you i don't know

8 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
yKpoI14uk [10]

Answer:

Confidence Interval in 95% confidence level for the quality rating is (6.06,7.46)

Step-by-step explanation:

Confidence Interval can be calculated using the formula M±ME where

  • M is the mean of the sample
  • ME is the margin of error in a given confidence level

Using the sample obtained from 50 business travelers we get

  • Mean of the sample is 6.76
  • standard deviation of the sample is 2.526

Margin of error (ME) around the mean using the formula

ME=\frac{z*s}{\sqrt{N} } where

  • z is the corresponding statistic in 95% confidence level (1.96)
  • s is the standard deviation of the sample (2.526)
  • N is the sample size (50)

Using the numbers in the formula we get:

ME=\frac{1.96*2.526}{\sqrt{50} } ≈ 0.70

Then the confidence interval becomes 6.76±0.70

6 0
3 years ago
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