Answer:
49.7%
Step-by-step explanation:
A cdircle is located within a square.
<u>Area of the circle</u>
Area = 
, where r = 4 units.
Area Circle = 50.3 units^2
<u>Area of the square</u>
Area = l*w or l^2 for a square, since l = w
Area = (10 units)^2
Area = 100 units^2
<u>Area in the square but outside the circle</u>
This is the difference [Square minus Circle Areas]
Square minus Circle Areas = 100 - 50.3 or <u>49.7 units^2</u>
<u>Probability</u>
The probability of picking a point in the square that is not in the circle is the ration of the two areas: <u>[Outside Circle/Square]x100%</u>
<u></u>
<u>(</u>49.7 units^2)/(100 units^2)x100% = 49.7%
<u></u>
Answer:
D. 314 yds
Step-by-step explanation:
Given:
Diameter = 100 yds
Required;
Circumference of the circle
Solution:
Circumference of circle = πd
Plug in the value
Circumference = π × 100
= 314 yds (nearest whole number)
Divide 1/2 by 1/8 by doing Keep change flip. 1/2 divided by 1/8 turns to 1/2 x 8/1 =9/2 and then divide 9/2 like this 9 divided by 2= 2 1/2
I’m pretty sure it is 57?