Answer:
a) (x + 5) (x - 5)
b) (x + 5i) (x - 5i)
c) (x + (5i/2)) (x - (5i/2))
d) (x-1)(x-1)
e) x +i√3 +1) (x -i√3+1)
Step-by-step explanation:
To solve this, we will need to factorize each quadratic function making it equal to zero first and then proceeding to find x
a) f(x) = x²-25
x²-25 = 0
⇒(x + 5) (x - 5)
b) f(x)=x²+25
x² + 25 = 0
x²= -25
x = √-25
x = √25i
x = ±5i
⇒(x + 5i) (x - 5i)
c) f(x)=4x²+25
4x²+25 = 0
4x²= -25
x² = -25/4
x = ±√(-25/4)
x = ±(√25i)/2
x = ±5i /2
⇒(x + (5i/2)) (x - (5i/2))
d) f(x)=x²-2x+1
x²-2x+1 = 0
⇒(x - 1)²
e) f(x)=x²-2x+4
x²-2x+4 = 0
x²-2x = -4
x²-2x +1 = -4 +1
x²-2x + 1 = -3
(x-1)² +3 = 0
(x-1)²= -3
x-1 = √-3
x = ±√3i +1
⇒(x +i√3 +1) (x -i√3+1)
<h3>Answer:</h3>
6 in
<h3>Explanation:</h3>
CG is 2/3 the length of median CM, where M is the midpoint of AB. M is the center of the circumscribing circle, which has radius 9 in, so CM is 9 in, and CG is 6 in.
Answer:
<h2>C) 6π cm²</h2>
Step-by-step explanation:
The shaded portion is a sector and the area of a sector is expressed as;
Area of sector = 
given 
= 60°, radius r = 6cm
area of the sector = 
area of the sector = 36π/6
area of the sector = 6πcm²
Step-by-step explanation:
Firstly, we have to find m∠J.
Since all the angles of a Δ equal 180°, angles J, L, and K should have a sum of 180°.
So,
m∠J + m∠L + m∠K = 180°
The diagram shows us that ∠L = 49° and ∠K = 90°, so we plug in those numbers in the equation.
m∠J + 49° + 90° = 180°
Then we simplify
m∠J + 139° = 180°
Subtract 139° to both sides
∠J = 41
Now the other angles.
Since ΔJKL ~ ΔRST, then ∠J ≅ ∠R, ∠K ≅ ∠S, and ∠L ≅ ∠T
Meaning, m∠J = m∠R, m∠K = m∠S, and m∠L = m∠T
Since we know m∠J = 41°, m∠K = 90°, and m∠L = 49° we could plug those in so...
41° = m∠R , 90° = m∠S , and 49° = m∠T
