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Fudgin [204]
3 years ago
6

(-7 - 10y + 6y2) + (4 + 3y)​

Mathematics
1 answer:
Naddik [55]3 years ago
8 0

Answer:

6y^2-7y-3

Step-by-step explanation:

<u>(-7-10y+6y^2)+(4+3y)</u>

<u>-7-10y+6y^2+4+3y </u><u><em>(Plus before brackets means the numbers stays the same)</em></u>

<u>6y^2+3y-10y+4-7</u><u><em> (Arrange them)</em></u>

<u>6y^2-7y-3 </u><u>(Do the maths)</u>

<u />

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The volume of the Atlantic Ocean is about 3.1⋅10173.1 \cdot 10^{17}3.1⋅10173, point, 1, dot, 10, start superscript, 17, end supe
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Answer: The annual flow of the Mississippi river would fit in the Atlantic ocean 4.92\times10^5 times.

Step-by-step explanation:

Given: Volume of Atlantic Ocean= 3.1\times10^{17} cubic meters

Annual flow of Mississippi river = 6.3\times10^{11} cubic meters.

then, the number of times the annual flow of the Mississippi river would fit in the Atlantic ocean = \dfrac{\text{ Volume of Atlantic Ocean}}{\text{Annual flow of Mississippi river}}

=\dfrac{3.1\times10^{17}}{6.3\times10^{11}}\ \ \=0.492063492063\times10^{17-11}\ \ [\dfrac{a^m}{a^n}=a^{m-n}]\\\\=0.492063492063\times10^6\approx4.92\times10^5

Hence,  the annual flow of the Mississippi river would fit in the Atlantic ocean 4.92\times10^5 times.

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If h (r)= 2/3 r - 6, what is the value of h(-9)?
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Answer:

h(-9)=-\frac{2}{33}

Step-by-step explanation:

The given expression is h(r)=\frac{2}{3r-6}

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This is the same as:

h(-9)=-\frac{2}{33}

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3 years ago
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