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VashaNatasha [74]
3 years ago
12

If h (r)= 2/3 r - 6, what is the value of h(-9)?

Mathematics
1 answer:
Bad White [126]3 years ago
3 0

Answer:

h(-9)=-\frac{2}{33}

Step-by-step explanation:

The given expression is h(r)=\frac{2}{3r-6}

We want to find the value of h(-9).

We substitute r=-9 to obtain:

h(-9)=\frac{2}{3(-9)-6}

We multiply out to obtain:

h(-9)=\frac{2}{-27-6}

We simplify the denominator to obtain:

h(-9)=\frac{2}{-33}

This is the same as:

h(-9)=-\frac{2}{33}

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