Which decimal is equivalent to 8 3/5 ?

At a sale, a table is being sold for 27% of the regular price. The sale price is $156.60.

8_murik_8 [283]

Answer:

$580

Step-by-step explanation:

Original price = $156.60 / 0.27

Original price = $580

7 0

3 years ago

)How many triangles can be made if one angle is 95° and another angle is acute?

OlgaM077 [116]

More than 2 ... there is a right and a obtuse i think

7 0

3 years ago

Dan weighs 205 pounds but is only 5 feet 8 inches tall. Evan is 6 feet tall. How much would you expect Evan to weigh if they hav

Rina8888 [55]

Answer:

Around 217 pounds

Step-by-step explanation:

Let's convert the height into inches.

5 feet 8 = $5\cdot12 + 8 = 60 + 8 = 68$

6 feet $= 6\cdot12 = 72$ .

We can set up a proportion

$\frac{205}{68} = \frac{x}{72}$

We can use the cross products property to find x.

$205\cdot72=14760\\\\\\14760\div68\approx217$

Hope this helped!

4 0

3 years ago

Read 2 more answers

Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave

Colt1911 [192]

Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\sigma}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

$P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\ \\ =1-P(z\ \textless \ -0.5410) \\ \\ =1-0.29426=\bold{0.7057}$

Part B:

</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

</span> $P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}$

7 0

3 years ago

Send answer really need it

Travka [436]

Answer:

DO U KNOW HOW TO GET MORE POINTS?

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers