Answer:
We start with the equation:
A: 3*(x + 2) = 18
And we want to construct equation B:
B: X + 2 = 18
where I suppose that X is different than x.
Because in both equations the right side is the same thing, then the left side also should be the same thing, this means that:
3*(x + 2) = X + 2
Now we can isolate the variable x.
(x + 2) = (X + 2)/3
x = (X + 2)/3 - 2
Then we need to replace x by (X + 2)/3 - 2 in equation A, and we will get equation B.
Let's do it:
A: 3*(x + 2) = 18
Now we can replace x by = (X + 2)/3 - 2
3*( (X + 2)/3 - 2 + 2) = 18
3*( (X + 2)/3 ) = 18
3*(X + 2)/3 = 18
(X + 2) = 18
Which is equation B.
Answer:
2, 5, 9, 19
Step-by-step explanation:
Using the recursive formula f(n) = 2f(n - 2) + f(n - 1)
with f(1) = 2 and f(2) = 5
f(3) = 2f(3 - 2) + f(3 - 1)
= 2f(1) + f(2) = (2 × 2) + 5 = 4 + 5 = 9
f(4) = 2f(4 - 2) + f(4 - 1)
= 2f(2) + f(3) = (2 × 5) + 9 = 10 + 9 = 19
Answer:
$37.50
Step-by-step explanation:
50*.25=12.50
Take $50 - 12.50 = 37.50
Sounds to me as tho you are to graph 3x+5y<10, and that after doing so you are to restrict the shaded answer area created by the "constraint" inequality x≤y+1. OR x-1 ≤ y OR y≥x-1. If this is the correct assumption, then please finish the last part of y our problem statement by typing {x-y<=1}.
First graph 3x+5y = 10, using a dashed line instead of a solid line.
x-intercept will be 10/3 and y-intercept will be 2. Now, because of the < symbol, shade the coordinate plane BELOW this dashed line.
Next, graph y=x-1. y-intercept is -1 and x intercept is 1. Shade the graph area ABOVE this solid line.
The 2 lines intersect at (1.875, 0.875). To the LEFT of this point is a wedge-shaped area bounded by the 2 lines mentioned. That wedge-shaped area is the solution set for this problem.
<span>if you're finding the x intercept, y is ALWAYS 0, so in this, you can just get rid of the -4y because you know that it's 0, so you're left with 2x=12 divide by 2 on both sides so you find x intercept is (6,0) on the graph
the y works the same way, if you're looking for the y, you know that the x is zero, so you're left with -4y=12, divide by -4y on both sides and you end up with the y intercept being (0,-3)
x int.= (6,0)
y int.= (0,-3)
by the way, when it's written like that, it's called standard form, so to find the intercepts on 2x=12+4y, you'd have to convert it into standard form (Ax=By=C) so you subtract 4y on both sides to make it 2x-4y=12, and then once you have it like that you can do the math to find the y and x intercepts.
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