Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
9514 1404 393
Answer:
- 113.04, 4, 452.16
- 78.5, 11, 863.5
- 153.86, 10, 1538.6
Step-by-step explanation:
When calculations are repetitive, I like to let a calculator or spreadsheet do them. Here we have used the formula for the base area:
B = πr² = 3.14×r²
In the second figure, the radius is half the diameter, so is 5 units.
The table in the attachment lists the base area B, the height h (from the figures), and the volume V. These are the values that you need to drag and drop to the boxes in your problem.
V = 113.04 · 4
V = 452.16 units³ . . . showing how the numbers are used in the first figure
To find the surface area of the cube using the formula, you would substitute in 2 1/2 for the length of the side.
SA = 6 x 2.5 x 2.5
SA = 37.5 ft.²
You are finding the area of one face (2.5 x 2.5) and multiplying it by six because there are six groups of this.
Answer:
7y+21
Step-by-step explanation: i solve it hope this help.
Answer:
x ≥ 9 and x < 5
Step-by-step explanation:
See the line graph of a compound inequality shown in the attached photo.
Inequality has two parts. The right-hand part is shown by an arrow that is more than 9 and including 9.
So, the equation of inequality for this part is x ≥ 9.
Again, the left-hand part of the inequality graph shows another arrow which is less than 5 but not including 5.
So, the equation of inequality for this part is x < 5
Therefore, compound inequality is x ≥ 9 and x < 5 (Answer)
