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ivann1987 [24]
3 years ago
11

The part of the computer that provides access to the Internet is the

Computers and Technology
2 answers:
-Dominant- [34]3 years ago
6 0

Answer:

c

Explanation:

Minchanka [31]3 years ago
3 0
I think that it is c
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You need to access the registry on your windows 10 computer how do you do this
Nikitich [7]

Press the Win and R keys together and the Run dialog box will pop up. Type regedit in the dialog box and you will then have access to the registry.

8 0
3 years ago
Primary storage is electronic storage connected directly to the CPU. true or false​
Helen [10]

Answer:

I think it's true

Explanation:

I don't know but If I'm wrong tell me?

7 0
2 years ago
The game begins with the player having 20 POINTS
kompoz [17]

Answer:

Following are the code to this question:

import random#import package for using random method  

def rolling_dice(): #defining method rolling_dice that uses a random number to calculate and add value in dice1 and dice2 variable

   dice1 = random.randint(1,6)

   dice2 = random.randint(1,6)

   return dice1 + dice2

def rolling(): # defining method rolling

   n_roll = 0  # defining num variable that initial value that is 0.

   p = 20 # defining variable p for looping, that points in between 1 and 59

   while p > 0 and p < 60: # defining loop that counts value dice value two times  

       d = rolling_dice()#defining d variable that hold method value

       n_roll+= 1 #defining n_roll that increment n_roll value by 1

       if d == 7 or d == 11:# defining if block that uses the d variable that checks either 7 or 11, player won d in p variable

           p+= d   # use p variable that adds d variable

       elif d == 2 or d == 3 or d == 12:#defining elif block to that checks d variable by using or operator  

           p-= d#defining d variable that decreases d variable variable

       else: # defining else block

           p1 = d # using p1 variable that store d value  

           while True:# defining loop that calculates values

               d = rolling_dice()#defining d variable that holds method values

               n_roll += 1 #increment the n_roll value by 1

               if d == 7:#defining if block that checks d value equal to 7

                   p -= p1#subtract the value of p1 in p variable  

                   break # exit loop

               elif d == p:#defining elif block to check d value is equal to p

                   p += p1#adds the value of p1 in p variable  

                   break#using break keyword

   if p<= 0:#defining if block that checks p-value is less then equal to 0  

       print('Player lost')#using print method

   elif p>= 60:#defining else block that checks p-value is greater than equal to 60

       print('Player won')#using print method to print the value

   print('number of dice rolls:', n_roll)#use print method to print n_rolls value

rolling()

Output:

Player lost

number of dice rolls: 38

Explanation:

In the above-given python code, a method "rolling_dice" is declared, inside the method two-variable "dice1 and dice2" is declared, that uses the random method to calculate the value in both variable and use the return keyword to add both values.

  • In the next step, another method the "rolling"  is declared, inside the method "n_roll and p" is declared that assigns the values and use the two while loop, inside the loop if block is defined that calculates the values.
  • In the next step, a condition block is used that stores value in the p variable and use the print method to print the "n_roll" value.  
8 0
3 years ago
Make sure to read all of these specifications carefully. Write a function, named array_shifter, that accepts an array of doubles
rosijanka [135]

Answer:

import java.util.Arrays;

public class num2 {

   public static void main(String[] args) {

//Create and initialize the first array        

double [ ]arr = {3.5, 5.6, 4.5, 6.7};

// Get the length of the array

       int n = arr.length;

      //Call the method Array Shifter inside the output statement

       System.out.println(Arrays.toString(array_shifter(arr,n)));

   }

   static double [] array_shifter(double [ ] doubleArray, int n){

       double [] narr = new double[n+1];

       //Loop through from index 1

       for(int i =0; i<narr.length-1; i++){

           narr[i] = doubleArray[i];

       }

       //Put a new element at the last index

       narr[narr.length-1] = 1.1;

       return narr;

   }

}

Explanation:

This is implemented in Java

Read detailed comments in the solution

The method array_shifter creates a new array that is one element larger than the array it received as argument and returns it

6 0
3 years ago
Which formulas would work to combine cells with first, middle, and last names from columns A through C and row 2 into a new cell
AURORKA [14]

Split? not really sure but i understand a bit of this..

6 0
3 years ago
Read 2 more answers
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