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MAXImum [283]
2 years ago
15

Find the equation of the line that passes through (-1,2)and is perpendicular to 2y=x-3

Mathematics
2 answers:
Anuta_ua [19.1K]2 years ago
6 0

Answer:

y = - 2x

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

2y = x - 3 ( divide the terms by 2 )

y = \frac{1}{2} x - \frac{3}{2} ← in slope- intercept form

with slope m = \frac{1}{2}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{1}{2} } = - 2 , then

y = - 2x + c ← is the partial equation

To find c, substitute (- 1, 2) into the partial equation

2 = 2 + c ⇒ c = 2 - 2 = 0

y = - 2x ← equation of the perpendicular line

Umnica [9.8K]2 years ago
4 0
Sorry I don’t have roller
Hope it’s right
Best luck with your studying

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