Find the equation of the line that passes through (-1,2)and is perpendicular to 2y=x-3
2 answers:
Answer:
y = - 2x
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
2y = x - 3 ( divide the terms by 2 )
y = x -
← in slope- intercept form
with slope m =
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= - 2 , then
y = - 2x + c ← is the partial equation
To find c, substitute (- 1, 2) into the partial equation
2 = 2 + c ⇒ c = 2 - 2 = 0
y = - 2x ← equation of the perpendicular line
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Answer:
Therefore,
l(AB) = 15 units
Step-by-step explanation:
Given:
AD = DC
angle DBA = angle DBC = 90°
AB = 5x
CB = 4x - 3
To Find:
AB = ?
Solution:
In Δ ABD and Δ CBD
AD ≅ DC ……….{Given}
∠ DBA ≅ ∠ DBC …………..{measure of each angle is 90° given}
DB ≅ DB ....……….{ Reflexive property}
Δ ABD ≅ Δ CBD ..........….{By Hypotenuse Leg Theorem}
∴ AB ≅ CB ..............{corresponding sides of congruent triangles}
on substituting the values we get
Now we require AB
Therefore,
l(AB) = 15 units