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3 years ago

Is anyone still in class, if you are can we do a troll?

Mathematics

2 answers:

Step2247 [10]3 years ago

8 0

Answer:

Some schools have special z.oom meetings which only let in participants with there email. You also can't sign in with two devices.

Step-by-step explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

mars1129 [50]3 years ago

4 0

Answer: This site is only for education related questions. You should only answer or ask questions. That's what we are here for. Whoever is reading this answer, please spread it to stop people from zooming, hurting others, posting non-related to education, or just communicating with others because this is not what Brainly is for. Thank you.

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Write a real world problem that involves classifying a quadrilateral

nignag [31]

You have a table is a quadrilateral, but you don't know the type of quadrilateral it is. It has four equal sides and 2 sets of parallel sides. What could it be?
Hope this helps!

5 0

4 years ago

Which of the following graphs is f(2) = 5

ser-zykov [4K]

Answer:

None.

Step-by-step explanation:

Where are the graphs? We need the extra information to complete this problem.

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3 years ago

noteooks come in four colors red, blue, green, and purple they also come in 2 sizes five subject and 3 subject how many possible

aalyn [17]

Answer:

Step-by-step explanation:

4×2×3 is 2..........................

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2 years ago

(Sin 1)^2 (sin 2)^2 ... (sin 360)^2

Lemur [1.5K]

$\sin360^\circ=0$ , so the product is $0$ .

6 0

3 years ago

How do you solve 1/x + 1/y + 1/z = 1 for z?

garri49 [273]

Answer:

$\large\boxed{z=\dfrac{xy}{xy-x-y}}$

Step-by-step explanation:

$\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z}=1\qquad\text{multiply both sides by}\ xyz\neq0\\\\xyz\cdot\dfrac{1}{x}+xyz\cdot\dfrac{1}{y}+xyz\cdot\dfrac{1}{z}=xyz\cdot1\qquad\text{simplify}\\\\yz+xz+xy=xyz\qquad\text{subtract}\ xy\ \text{from both sides}\\\\xz+yz=xyz-xy\qquad\text{subtract}\ xyz\ \text{from both sides}\\\\xz+yz-xyz=-xy\qquad\text{distribute}\\\\(x+y-xy)z=-xy\qquad\text{divide both sides by}\ (x+y-xy)\\\\z=\dfrac{-xy}{x+y-xy}\\\\z=\dfrac{-xy}{-(xy-x-y)}\\\\z=\dfrac{xy}{xy-x-y}$

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3 years ago