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stepan [7]
3 years ago
13

Solve 4d = 1/3a. 4/3b. 1/7c. 1/12d. 1/4

Mathematics
1 answer:
ELEN [110]3 years ago
4 0
4d = 1/3
d = 1/3/4
d = 1/12
Thus, c is the correct choice.
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PLEASEEEE I NEEED HEEELPPP THIS IS AND A SUBTRACT INTEGERS BUT I DON’T UNDERSTAND
Ann [662]

Answer:

-5

Step-by-step explanation:

Subtracting a negative is just like adding a positive. A way to think about this is that the negative cancel each other out are you left with a positive number.

You can rewrite this as -87 + 82.

Then, you solve and get -5.

6 0
3 years ago
Read 2 more answers
∠A and \angle B∠B are supplementary angles. If m\angle A=(2x-14)^{\circ}∠A=(2x−14)
nevsk [136]

Answer:

∠ A = 66°

Step-by-step explanation:

Supplementary angles sum to 180° thus

∠ A + ∠ B = 180 , substitute values

2x - 14 + 3x - 6 = 180 , that is

5x - 20 = 180 ( add 20 to both sides )

5x = 200 ( divide both sides by 5 )

x = 40

Thus

∠ A = 2x - 14 = 2(40) - 14 = 80 - 14 = 66°

8 0
3 years ago
The original line has the equation of y=-2x+8
enot [183]

The new equation of line that is perpendicular to the original that goes through the point (6, -1) in slope intercept form is y = \frac{1}{2}x - 4

<h3><u>Solution:</u></h3>

Given that original line has the equation of y = -2x + 8

We have to write a new equation that is perpendicular to the original that goes through the point (6, -1)

Let us first find slope of original line

<em><u>The slope intercept form of line is given as:</u></em>

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing the slope intercept form and given original equation, we get "m = -2"

Thus slope of original line "m" = -2

We know that product of slope of a line and slope of line perpendicular to it are always -1

slope of original line x slope of line perpendicular to it = -1

\begin{array}{l}{-2 \times \text { slope of line perpendicular to it }=-1} \\\\ {\text { slope of line perpendicular to it }=\frac{1}{2}}\end{array}

Let us find equation of line with slope m = 1/2 and passes through point (6, - 1)

Substitute m = \frac{1}{2} and (x, y) = (6, -1) in eqn 1

-1 = \frac{1}{2} \times 6 + c\\\\-1 = 3 + c\\\\c = -4

<em><u>Thus the required equation of line is:</u></em>

Substitute "c" = -4 and m = \frac{1}{2} in eqn 1

y = \frac{1}{2}x - 4

Thus the equation of line perpendicular to original line is found

7 0
3 years ago
A 2.5​ ft wide circular track for a camera dolly is set up for a movie scene. The two rails of the track form concentric circles
Deffense [45]

Answer:

15.71 ft

Step-by-step explanation:

Given that:

width of the circular track = 2.5ft

Suppose the radius of the inner circle is 57 ft since it is not given

Then the radius of the outer circle = (2.5 + 57) ft = 59.5 ft

The circumference of a circle = 2πr

For inner circle now, the circumference = 2 × π × 57 ft

For inner circle now, the circumference = 358.14 ft

For the outer circle, the circumference = 2 × π × 59.5 ft

For the outer circle, the circumference = 373.85 ft

The difference between the circumference of the outer wheel from the inner wheel shows how farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one​ turn

∴

= ( 373.85 - 358.14 ) ft

= 15.71 ft

6 0
3 years ago
2^5*5^2*(-6)^4<br> ___________<br> (-6)^2*2^3*5^2 simplify
gulaghasi [49]

Answer:

The answer is 144

Step-by-step explanation:

\frac{ {2}^{5}  \times  {5}^{2}  \times   { - 6}^{4} }{  {2}^{3}  \times  {5}^{2} \times  { - 6}^{2}  }

{2}^{2}  \times  {6}^{2}  =  \\ 4 \times 36 = 144

5 0
3 years ago
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