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3 years ago

Solve 4d = 1/3a. 4/3b. 1/7c. 1/12d. 1/4

Mathematics

1 answer:

ELEN [110]3 years ago

4 0

4d = 1/3
d = 1/3/4
d = 1/12
Thus, c is the correct choice.

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What is the interest earned on $3000 at a rate of 0.04 for three years? The formula is interest equals (principal) (rate) (time)

bekas [8.4K]

Answer:

The interest after 3 years is $360

Explanation:

Given the principal amount (P) = $3000

Rate of interest (R) = 0.04

Time period (T) is given as 3 years

The Simple Interest is calculated by the formula;

$SI = Principal \times Rate of Interest \times Time$

Substituting the values in the above formula,

$SI = 3000 \times 0.04 \times 3$

SI = $360

Therefore, the interest after 3 years is $360

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3 years ago

Greg rented a truck for one day there was a base fee of $16.99 and there was additional charge of $.89 for each mile driven Greg

julia-pushkina [17]

Let m represent the number of mile Greg drove. His rental charge was
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7 0

3 years ago

Evaluate the function at the given values F(y) = 4y^4 - 6y^2 + 8y - 15 At y = 2

otez555 [7]

F(2)= 4(16) - 6(4) + 8(2) - 15
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7 0

3 years ago

A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank

harkovskaia [24]

Answer:

The value is $P_o = \$ 561958.9$

Step-by-step explanation:

From the question we are told that

The capacity of the metal tank is $C = 2000 \ gallon$

The duration usage is $t = 15\ years \ ago$

The cost of 2000-gallon tank 15 years ago is $P = \$100,000$

The capacity of the second tank considered is $C_1 = 5,000$

The power sizing exponent is $e = 0.57$

The initial construction cost index is $u_1 = 180$

The new construction after 15 years cost index is $u_2 =600$

Equation for the power sizing exponent is mathematically represented as

$\frac{P_n}{P} = [\frac{C_1}{C} ]^{e}$

=> Here $P_n$ is the cost of 5,000-gallon tank as at 15 years ago

$P_n = [\frac{5000}{2000} ] ^{0.57} * 100000$

$P_n = \$168587.7$

Equation for the cost index exponent is mathematically represented as

$\frac{P_o}{P_n} = \frac{u_2}{u_1}$

Here $P_o$ is the cost of 5,000-gallon tank today

$\frac{P_o}{168587.7} = \frac{600}{180}$

=> $P_o = \frac{600}{180} * 168587.7$

=> $P_o = \$ 561958.9$

8 0

3 years ago

posledela

Answer:

red +blue marbles :- 15 +13=28 marbles.

yellow marbles:- 50+28=22 marbles.

probability of yellow marble :- 22/50 i.e 11/25

5 0

3 years ago