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melamori03 [73]
2 years ago
12

Which is equal to the cos ÐR?PLEASE HELP ME

Mathematics
1 answer:
inna [77]2 years ago
4 0

Answer: 4/5 = .8

cos adj/hyp of r is .8

HOWEVER...

I’m assuming it’s talking about angle R...

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A cone is 3 inches high and has a base with a surface area of 7 square inches. What is the volume of the cone?
lawyer [7]

Answer: the answer should be 7

Step-by-step explanation:  V=πr2h

3=π·1.52·3

3≈7.06858

you can find the radius for the area of the base 7 by dividing by \pi like such 7/3.1459 the squared because remember its in r2 form which give you 1.5 then plug this in for one of two ways to solve A·\pi 1/3 or V=πr2h

4 0
3 years ago
A circle is centered at the point (5, -4) and passes through the point (-3, 2).
zepelin [54]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

As we know the given points

Center = (5, -4)

and

Point on circle = (-3,2)

The distance between point on circle and center will give us the radius of circle

So,

The formula for distance is:

\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10

The standard form of equation of circle is:

(x-h)^{2}+(y-k)^{2}=r^{2}

where h and k are the coordinates of the center. So putting in the value:

(x-5)^{2}+(y-(-4))^{2}=(10)^{2}\\(x-5)^{2}+(y+4)^{2}=100

8 0
3 years ago
Please help, will Mark brainliest if correct.
pochemuha
The answer is: w || t
4 0
3 years ago
There are 2 mice 4 cats and 6 dogs. Write two sentences that describe a ratio of types of animals in this collection. What is th
svp [43]
The ratio would be 2:4:6. For every 2 mice, there is 4 cats, and 6 dogs. This could be simplified to 1:2:3 by dividing all by 2.
3 0
3 years ago
Determine a and k so the given points are on the graph of the function.
Margarita [4]

Answer:

  y = -7(x +1)² +35

Step-by-step explanation:

The given quadratic equation has two parameters you are asked to find. When you fill in the given point values, the result is two linear equations in the two unknown parameters. You can solve these equations in any of the usual ways.

__

<h3>equation for point (1, 7)</h3>

  y = a(x +1)² +k

  7 = a(1 +1)² +k

  7 = 4a +k

<h3>equation for point (2, -28)</h3>

  -28 = a(2 +1)² +k

  -28 = 9a +k

<h3>solution</h3>

The first equation can be subtracted from the second equation to eliminate the k variable. (This is solving by <em>elimination</em>.)

  (-28) -(7) = (9a +k) -(4a +k)

  -35 = 5a . . . . . . . . simplify

  -7 = a . . . . . . . . divide by 5

Using the first equation, we can find k.

  7 -4a = k . . . . . subtract 4a

  7 -4(-7) = k . . . . substitute for 'a'

  35 = k

The parameter values are a = -7, and k = 35. The quadratic equation is ...

  y = -7(x +1)² +35

3 0
2 years ago
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