Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
The answer is 0.555556 I really hope this helps!
If the insurance pays $2,000, but the test itself cost $2,750, you simply subtract.
$2,750-$2,000= $750
Therefore Bobby has to pay $750
1) (m³n⁵)(mn⁴)
-----------------
m⁻³n²
Simplify.
m⁴n⁹
-------
m⁻³n²
When the bottom power is a negative, you add it to the power on top, & when the power is a positive, you subtract it.
m⁴ + m³ = m⁷
n⁹ - n² = n⁷
So, our answer for #1 is m⁷n⁷
2) 6a²b³
---------
4a
Please read rules in #1.
6 / 4 = 3/2 & a² - a = a
So, our answer is 3a
-----
2
3) 5⁶a⁶b³
---------
5²ab³
5⁶ - 5² = 5⁴ AND a⁶ - a = a⁵ AND b³-b³ = 0
So, our answer is 5⁴a⁵
Simplify 5⁴
5 × 5 × 5 × 5 = 625
So, our final answer is :
625a⁵
~Hope I helped!~
Multiply every coordinate by the scale factor 3
(-1,2,0) ----> (-3,6,0) is the answer