Given :
The diagonals of rhombus ABCD intersect at E.
∠CAD = 20°.
To Find :
The angle ∠CDA.
Solution :
We know, diagonals of a rhombus bisects each other perpendicularly.
So, ∠DEA = 90°.
In triangle ΔEAD :
∠EAD + ∠AED + ∠EDA = 180°
20° + 90° + ∠EDA = 180°
∠EDA = 70°
Now, we know diagonal of rhombus also bisect the angle between two sides .
So, ∠CDA = 2∠EDA
∠CDA = 2×70°
∠CDA =140°
Therefore, ∠CDA is 140°.
Answer:
3.96
Step-by-step explanation:
3.3÷5=0.66
6×0.66=3.96
True.
The diameter is the axis of symmetry of a circle.
The diameter divides the circle into two equal parts. Therefore, it can be considered an axis of symmetry. Everything on the right of the diameter is the same as everything on the left of the diameter.
answer
True.
