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Phoenix [80]
3 years ago
9

What is the justification for step 2 in the solution process?

Mathematics
1 answer:
Andre45 [30]3 years ago
3 0

Step-by-step explanation:

option A is the correct answer

the subtraction property of equality

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Divide: ((p^2-q^2)/(p+q)) ÷ ((p-q)/(p+q))
Pani-rosa [81]

Answer:

The answer is p+q

Step-by-step explanation:

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3 years ago
HELP ASAPP!!<br><br> Distribute:<br><br> 3(-2x + 9)
Dima020 [189]

Answer:

-6x+27

hope this helps

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Step-by-step explanation:

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3 years ago
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8(u-5)=8•u-8•5 identify the properties of real numbers illustrated by each statement
Nadya [2.5K]

Answer:

I think this is the answer you are looking for.

Step-by-step explanation:

Any value of  u  makes the equation true. All real numbers

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4 years ago
If x^2 +x-12 is a factor of x^3+ax^2-10x-b then find the values of a and b
Marysya12 [62]

Answer:

a=3

b=24

Step-by-step explanation:

If x^2+x-12 is a factor of x^3+ax^2-10x-b, then the factors of x^2+x-12 must also be factors of x^3+ax^2-10x-b.

So what are the factors of x^2+x-12?  Well the cool thing here is the coefficient of x^2[tex] is 1 so all we have to look for are two numbers that multiply to be -12 and add to be positive 1 which in this case is 4 and -3.-12=4(-3) while 1=4+(-3).So the factored form of [tex]x^2+x-12 is (x+4)(x-3).

The zeros of x^2+x-12 are therefore x=-4 and x=3.  We know those are zeros of x^2+x-12 by the factor theorem.  

So x=-4 and x=3 are also zeros of x^3+ax^2-10x-b because we were told that x^2+x-12 was a factor of it.

This means that when we plug in -4, the result will be 0. It also means when we plug in 3, the result will be 0.

Let's do that.

(-4)^3+a(-4)^2-10(-4)-b=0  Equation 1.

(3)^3+a(3)^2-10(3)-b=0  Equation 2.

Let's simplify Equation 1 a little bit:

(-4)^3+a(-4)^2-10(-4)-b=0

-64+16a+40-b=0

-24+16a-b=0

16a-b=24

Let's simplify Equation 2 a little bit:

(3)^3+a(3)^2-10(3)-b=0

27+9a-30-b=0

-3+9a-b=0

9a-b=3

So we have a system of equations to solve:

16a-b=24

9a-b=3

---------- This is setup for elimination because the b's are the same. Let's subtract the equations.

16a-b=24

9a-b=   3

------------------Subtracting now!

7a    =21

Divide both sides by 7:

 a   =3

Now use one the equations with a=3 to find b.

How about 9a-b=3 with a=3.

So plug in 3 for a.

9a-b=3

9(3)-b=3

27-b=3

Subtract 27 on both sides:

   -b=-24

Multiply both sides by -1:

    b=24

So a=3 and b=24

7 0
4 years ago
I=\int\limits{\frac{x}{x^{4} -8x^{2} +16} } \,
Ratling [72]

Answer:

Step-by-step explanation:

3 0
3 years ago
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