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3 years ago

The change in inventories,a component of aggregate supply, comprises roughly what percentage of the GDP

Mathematics

1 answer:

eduard3 years ago

5 0

Answer:

0.5percentage

Step-by-step explanation:

The change in inventories,a component of aggregate supply comprises roughly of 0.5percentage of GDP

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Angle GNH is congruent to angle KNL. Angle MNL is complementary to angle KNL. What is the measure of angle MNL?

Sliva [168]

Answer:

The measure of angle MNL is $42\°$

Step-by-step explanation:

see the attached figure to better understand the problem

In this problem we know that

angle GNH is congruent to angle KNL

$m$ -----> by vertical angles

$m$

Find the measure of angle MNL

$m$ ------> by complementary angles

Substitute and solve for m<MNL

$m$

5 0

3 years ago

Read 2 more answers

Benny sold half of his comic books and then bought 6 more. He now has 17. How many did he begin with ? i need to write it in num

Georgia [21]

Answer:

Step-by-step explanation:

1/2x + 6 = 17

subtract 6 from each side of the equation:

1/2x = 11

multiply both sides by 2:

x = 22

8 0

3 years ago

A video game displays 84 frames in 4 seconds on Penelope's computer. What is the rate in frames per second?

svetlana [45]

Answer: 21

Step-by-step explanation: 84/4 = 21

8 0

3 years ago

Questions (no partial grades if you don't show your work) 1. In a group of 6 boys and 4 girls, four children are to be selected.

mariarad [96]

Answer:

Total number of ways will be 209

Step-by-step explanation:

There are 6 boys and 4 girls in a group and 4 children are to be selected.

We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.

So the groups can be arranged as

(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)

Now we will find the combinations in which these arrangements can be done.

1 Boy and 3 girls = $^{6}C_{1}\times^{4}C_{3}=6\times4$ =24

2 Boy and 2 girls= $^{6}C_{2}\times^{4}C_{2}=\frac{6!}{4!\times2!}\times\frac{4!}{2!\times2!}=15\times6=90$

3 Boys and 1 girl = $^{6}C_{3}\times^{4}C_{1}=\frac{6!}{4!\times2!}\times\frac{4!}{3!}=\frac{6\times5\times4}{3 \times2} \times4=80$

4 Boys = $^{6}C_{4}=\frac{6!}{4!\times2!} =\frac{6\times 5}{2\times1}=15$

Now total number of ways = 24 + 90 + 80 + 15 = 209

7 0

3 years ago

What is 6,051 x 10^5 written in standard form?

Setler79 [48]

Answer:

605100

Step-by-step explanation:

6.051*10^5=605100

6 0

2 years ago