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3 years ago

Which ratios can form a proportion?

Mathematics

2 answers:

Firdavs [7]3 years ago

8 0

6/36, 5/30
these two are proportional, hope this helpsss

Oksi-84 [34.3K]3 years ago

7 0

B. is the correct answer I think.

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A hot tub that holds 300 gallons of water drains at a rate of 8 gallons write an equation that represents how many gallons of wa

Salsk061 [2.6K]

Answer:the number of gallons of water left in the tub after it has drained for x minutes is 300 - 8x

Step-by-step explanation:

A hot tub that holds 300 gallons of water drains at a rate of 8 gallons.

Let x represent the number of minutes for which the hot tub has drained water.

If the hot tub drains 8 gallons of water per minute, it means that in x minutes, the number of gallons of water that the hot tub would have drained is 8x

Therefore, the number of gallons of water left in the tub after it has drained for x minutes would be

300 - 8x

7 0

3 years ago

URGENT PLZ HELP ME!!!

hichkok12 [17]

Answer:

You would click at (0,-7)

Step-by-step explanation:

Definition of the minimum point:

"The minimum value of a function is the place where the graph has a vertex at its lowest point. In the real world, you can use the minimum value of a quadratic function to determine minimum cost or area."

Although this is not a quadratic, it still has a minimum point.

The minimum point here would be at it's lowest point

The minimum/lowest point is (0,-7)

4 0

3 years ago

Help. I need help with these questions ( see image).<br> Please show workings.

Andrew [12]

9514 1404 393

Answer:

4) 6x

5) 2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

$\text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}$

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

lim[h→0](f(x+h)-f(x))/h = 2ax +b

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0

3 years ago

Please help as soon as possible

Mice21 [21]

1 kilometer = 1000 meters so 12 kilometers = 12000 meters

10 laps (400 meters/lap) = 4000 meters

12000/4000 = 3

Answer: 3 days

4 0

3 years ago

In a lab, a substance was cooked by 42 C over a period of 7 hours at a constant rate. What was the change in temperature each ho

Mekhanik [1.2K]

Given that we have the change in temperature over 7 hours and we are looking for the change over 1 hour, we can divide the total change in temperature by 7. Thus, the change in temperature would be $\frac{42}{7} C^{\circ}$ .

Additionally, this can be solved by equations:

$\dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = \dfrac{x \,\textrm{C}^{\circ}}{1 \,\textrm{hour}}$

$1 \,\textrm{hour} \cdot \dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = x \,\textrm{C}^{\circ}$

$\dfrac{42}{7} \,\textrm{C}^{\circ} = x \,\textrm{C}^{\circ}$

$\dfrac{42}{7} = x$

By using two different methods, we can determine that the change each hour was equal to 42/7 C° per hour.

6 0

3 years ago