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Which has a value closest to 9?<br> 63<br> 110<br> 99<br> 183

kirill [66]

Answer:

64

Step-by-step explanation

6 0

3 years ago

The dimensions of a rectangular dining room are 18 feet by 16 feet. If a scale factor of 1/4 is used to make a scale model of th

vivado [14]

Since the dimension of the scale model is fourth of dimensions of the room, divide by 4 the given dimensions.

new dimensions:
= 18 ft / 4 = 9/2 ft
= 16 ft / 4 = 4 ft

The area is calculated by multiplying the dimensions,
Area = (9/2 ft)(4 ft) = 18 ft²

Therefore, the area of the scale model is equal to 18 ft².

5 0

4 years ago

Solve for the indicated variable. Include all of your work in your answer. Submit your solution.

levacccp [35]

Answer:

The answer is $L=\frac{A}{W}$

Step-by-step explanation:

In order to determine the answer, we have to know about equation. In an equation, we have variables, some of them depend on the others. If we want to know the value of one variable ( the dependent variable), we have to free it in any side of the equation.

In this case, we want to know the value of "L" variable. So we free that variable to the right side of the equation.

$A=LW$

We divide each side by "W":

$\frac{A}{W}=\frac{LW}{W}$

We simplify the "W" in the right side:

$\frac{A}{W}=L$

Finally, the solution for "L" is :

$L=\frac{A}{W}$

6 0

3 years ago

Read 2 more answers

For the right triangle shown, which expression represents the length of CB?

Rudik [331]

Answer:

B) 6 tan(35°)

Step-by-step explanation:

from the right angle tan° = opposite / adjacent

therefore tan (35°) = (x) / 6

by multiplying 6 to both sides

tan (35°) * 6 = (x) / 6 * 6

therefore (x) = 6 tan (35°)

5 0

3 years ago

PLEASE HELP!! what is the equation for the parabolic function that goes through the points (-3, 67) (-1, 1) and has a stretch fa

barxatty [35]

Answer:

$f(x)=9(x+\frac{1}{6})^2-\frac{21}{4}$

Step-by-step explanation:

So, we need to find the equation of a parabolic function that goes through the points (-3,67) and (-1,1) and has a stretch factor of 9.

In other words, we want to find a quadratic with a vertical stretch of 9 that goes through the points (-3,67) and (-1,1).

To do so, we first need to write some equations. Let's use the vertex form of the quadratic equation. The vertex form is:

$f(x)=a(x-h)^2+k$

Where a is the leading coefficient and (h,k) is the vertex.

Since a is the leading coefficient, it's also our stretch factor. Thus, let a equal 9.

Also, we have two points. We can interpret them as functions. In other words, (-3,67) means that f(-3) equals 67 and (-1,1) means that f(-1) equals 1. Write the two equations:

$f(x)=a(x-h)^2+k\\f(-3)=67=9((-3)-h)^2+k$

And:

$f(x)=a(x-h)^2+k\\f(-1)=1=9((-1)-h)^2+k$

Now, we essentially have a system of equations. Thus, to find the original equation, we just need to solve for the vertex. To do so, first isolate the k term in the second equation:

$1=9(-1-h)^2+k\\k=1-9(-1-h)^2$