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3 years ago

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Find the unknown dimension of a rectangle if its perimeter is 254 meters and one dimension measures 6 meters. Use labeled sketch

es and equations to model and solve this problem. Show your work. Label your answer with the correct units.
please answer

1 answer:

12345 [234]3 years ago

4 0

Answer:2

Step-by-step explanation:

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A. 2,464 cm^2<br> B. 2,364 cm ^2<br> C. 1,464 cm^2<br> D. 1,364 cm^2

Nastasia [14]

Answer:

c 1464 cm ^2 is the answer

5 0

3 years ago

John is going camping, and he needs to buy a tent. The outdoor store has one that cost $90, but it's on sale for 25% off. What i

pochemuha

Answer:

A

Step-by-step explanation:

<em>Okay so, im not the best at explaining, but so we have a percentage. its 25%. you want to take the 25% and put it over 100 because a percentage is a number or ratio expressed as a fraction of 100. so it will be written as 25%/100</em>

<em />

<em>divide 25 by 100 and you get 0.25, correct? so that's one step further towards the answer.</em>

<em>then we write x/90 because we don't know (well we do) what we're gonna put. but, we're gonna multiply 0.25 by 90 and we get 22.5, which is equivalent to </em><em>22.50</em><em>.</em>

7 0

3 years ago

Read 2 more answers

What is the following product?

umka21 [38]

Answer:

10 sqrt 3.

Step-by-step explanation:

sqrt30 = sqrt10 * sqrt 3

so sqrt30 * sqrt10

= sqrt10 * sqrt10 * sqrt3

= 10 sqrt 3.

5 0

3 years ago

POSSIBLE POINTS: 16.67

Andrews [41]

Answer:

24 inches

Step-by-step explanation:

7 0

2 years ago

A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the pr

worty [1.4K]

Answer: The probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

Step-by-step explanation: Given that a bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles.

Let S be the sample space for the experiment of pulling a marble.

Then, n(S) = 12 + 8 + 5 = 25.

Let, E, F and G represents the events of pulling a red marble, a blue marble and a green marble respectively.

The, n(E) = 12, n(F) = 8 and n(G) = 5.

Therefore, the probabilities of each of these three events E, F and G will be

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{12}{25}=\dfrac{12}{25}\times100\%=48\%,\\\\\\P(F)=\dfrac{n(F)}{n(S)}=\dfrac{8}{25}=\dfrac{8}{25}\times100\%=32\%,\\\\\\P(G)=\dfrac{n(G)}{n(S)}=\dfrac{5}{25}=\dfrac{5}{25}\times100\%=20\%.$

Now, the probability of pulling three green marbles out with replacement is given by

$P(G)\times P(G)\times P(G)=\dfrac{5}{25}\times\dfrac{5}{25}\times \dfrac{5}{25}=\dfrac{1}{125}=\dfrac{1}{125}\times100\%=0.8\%.$

Thus, the probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

4 0

3 years ago