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Archy [21]
3 years ago
10

Write a program that prints the sum of the even numbers and the products of odd numbers on the screen

Computers and Technology
1 answer:
ss7ja [257]3 years ago
4 0

Answer:

The program in Python is as follows:

n = int(input("Number of inputs: "))

total = 0; product = 1

for i in range(n):

   num = int(input(": "))

   if num%2 == 0:

       total+=num

   else:

       product*=num

print("Sum of even: ",total)

print("Product of odd: ",product)

Explanation:

This prompts the user for the number of inputs, n

n = int(input("Number of inputs: "))

This initializes sum (total) to 0 and products to 1

total = 0; product = 1

This iterates through n

for i in range(n):

This gets the inputs

   num = int(input(": "))

If input is even, calculate the sum

<em>    if num%2 == 0:</em>

<em>        total+=num</em>

If otherwise, calculate the product

<em>    else:</em>

<em>        product*=num</em>

Print the required outputs

<em>print("Sum of even: ",total)</em>

<em>print("Product of odd: ",product)</em>

<em />

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noname [10]
I believe the correct answer is the first option. The primary difference between 3g and 4g cellular systems would be that 4g systems have faster transmission as compared to 3g. The G would mean generation. The very difference of both is their speeds.
4 0
3 years ago
How many bits can a memory chip with the below configuration support? For full credit, show how you got the answer.
tatiyna

Answer:

Total Memory= 4 KB = 4096 bytes = 32768 bits

Explanation:

<em><u>1. Data lines are 8 From D0 to D7</u></em>

so

Total memory at single address locations is 8 bits.

<em><u>2. Address lines are 12 (A0 to A11)</u></em>

There are 12 address lines but 3 out 12 are for selction of chip or memory bank.

so only 9 pins are there to address the locations on one chip.

Total No. of address locations on single chip = 2^9 = 512 locations

as 1 location is 1 byte so total memory of single chip is 512 bytes.

<u><em>3. Total Memory Bank </em></u>

There are total 3 selection pins for memory bank.

so

Total chips = 2^3 = 8.

<em><u>4. Total Memory </u></em>

Total size of 1 chip = 512 bytes

Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb

<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>

5 0
3 years ago
Which input and output pair is correct for a bicycle?
mrs_skeptik [129]

Answer:

I'm pretty sure its B.

Explanation:

Input: Force is applied to the pedals by the rider's feet then..

Process: the chain and gear system convert the energy to cause...

Output: the rear wheels to turn and make the bike go foward

6 0
3 years ago
3.29 LAB: Login name Write a program that creates a login name for a user, given the user's first name, last name, and a four-di
romanna [79]

Answer:

In C++:

#include <iostream>

using namespace std;

int main(){

   string fname,lname; int num;

   cout<<"Firstname: "; cin>>fname;

   cout<<"Lastname: "; cin>>lname;

   cout<<"4 digits: "; cin>>num;

   string login = lname;

   if(lname.length()>=5){

       login = lname.substr(0, 5);    }

   login+=fname.substr(0,1)+to_string(num%100);

   cout<<login;

   return 0;

}

Explanation:

See attachment for explanation where I used comments to explain each line

Download cpp
4 0
3 years ago
Because filling a pool/pond with water requires much more water than normal usage, your local city charges a special rate of $0.
nevsk [136]

Answer:

In C:

#include <stdio.h>

int main(){

   float length, width, depth,poolvolume,watervolume,charges;

   printf("Length (feet) : ");    scanf("%f",&length);

   printf("Width (feet) : ");    scanf("%f",&width);

   printf("Depth (feet) : ");    scanf("%f",&depth);

   poolvolume = length * width* depth;

   watervolume = length * width* (12 * depth - 3)/12;

   charges = 100 + 0.77 * watervolume;

   printf("Invoice");

   printf("\nVolume of the pool: %.2f",poolvolume);

   printf("\nAmount of the water needed: %.2f",watervolume);

   printf("\nCost: $%.2f",charges);

   printf("\nLength: %.2f",length);

   printf("\nWidth: %.2f",width);

   printf("\nDepth: %.2f",depth);

   printf("\nMr. Royal [Replace with your name] ");

   return 0;}

Explanation:

This declares the pool dimensions, the pool volume, the water volume and the charges as float    

float length, width, depth,poolvolume,watervolume,charges;

This gets input for length

   printf("Length (feet) : ");    scanf("%f",&length);

This gets input for width

   printf("Width (feet) : ");    scanf("%f",&width);

This gets input for depth

   printf("Depth (feet) : ");    scanf("%f",&depth);

This calculates the pool volume

   poolvolume = length * width* depth;

This calculates the amount of water needed

   watervolume = length * width* (12 * depth - 3)/12;

This calculates the charges

   charges = 100 + 0.77 * watervolume;

This prints the heading Invoice

printf("Invoice");

This prints the volume of the pool

   printf("\nVolume of the pool: %.2f",poolvolume);

This prints the amount of water needed

   printf("\nAmount of the water needed: %.2f",watervolume);

This prints the total charges

   printf("\nCost: $%.2f",charges);

This prints the inputted length

   printf("\nLength: %.2f",length);

This prints the inputted width

   printf("\nWidth: %.2f",width);

This prints the inputted depth

   printf("\nDepth: %.2f",depth);

This prints the name of the programmer

   printf("\nMr. Royal [Replace with your name] ");

   return 0;}

<em>See attachment for program in text file</em>

Download txt
3 0
2 years ago
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