Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
822 hours. 10.25x822 is $8,425.50.
Nobody can solve this without any further information?
Answer:
swap the middle two steps to put them in order
Step-by-step explanation:
The steps in order would be ...
- -11 -5z = 30z +24 . . . . . eliminate parentheses
- -11 = 35z +24 . . . . . . . . add 5z
- -35 = 35z . . . . . . . . . . . . subtract 24
- -1 = z . . . . . . . . . . . . . . . . divide by 2