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3 years ago

What is the constant of variation for the inverse variation? xy = 8

Mathematics

1 answer:

Advocard [28]3 years ago

6 0

Answer:

Step-by-step explanation:

The constant of variation is the constant in the equation: 8.

___

The equation can be rewritten to be

y = 8/x

Compared to the generic equation for inverse variation, ...

y = k/x

we see that the constant of variation (k) is the constant in the given equation, 8.

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Sherry brings two containers of cookies to a party. Each container contains 6 cookies. Sally shows up with a dozen cookies. Sand

kotykmax [81]

Answer:

22 cookies

Step-by-step explanation:

A dozen items means 12 number of items.

Number of cookies brought by Sherry = No. of containers multiplied by number of cookies in one container

= 2 $\times$ 6 = 12

Number of cookies brought by Sally = A dozen cookies = 12

Number of cookies brought by Sandy = 2

Number of cookies brought by Sherry, Sally and Sandy together = 12 + 12+2 = 26

Total number of cookies to be brought = 4 dozen = 48 cookies

Number of cookies to be brought by Harry = Total number of cookies to be brought - Number of cookies brought by Sherry, Sally and Sandy together

48 - 26 = <em>22 cookies</em>

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3 years ago

Easton is deciding between two different movie streaming sites to subscribe to. Plan

muminat

Answer:

how do we graph on here

Step-by-step explanation:

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2 years ago

Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$