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ANTONII [103]
3 years ago
6

A code consists of a single digit number from 0-9 and a letter from the alphabet. What is the probability that the code is 3Z? W

rite your answer as a fraction in simplest form.
Mathematics
1 answer:
Nana76 [90]3 years ago
4 0
The probability of it being 3Z is 1/27
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Its B

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HELP!
maxonik [38]

Answer: 3x + 15 = 51

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Hope this helps :)

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The large rectangle below represents one whole. A large rectangle with 25 equal sections, 11 of which are shaded What percent is
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34. Which is the rule for the linear<br> function graphed below?
Ivahew [28]

Answer:

We can note that this part of the graph is a linear function. This means that is has a general form: y = mx + c where m is the slop and c is the y-intercept (value of y at x=0). For the slope, we will use the points (0,2) and (3,5) to calculate it as follows: m = (y2-y1)/(x2-x1) = (5-2)/(3-0) = 1 For the y-intercept, we can note that at x=0, the value of y is 2. This means that the equation of the first part of the graph is: y = x + 2

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/703068-which-rules-define-the-function-graphed-below.html

8 0
3 years ago
Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0
3 years ago
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