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3 years ago

Someone help me!!!!

Mathematics

1 answer:

Arada [10]3 years ago

8 0

Answer:

i think its A

Step-by-step explanation:

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Find a particular solution to y′′+25y=−40sin(5t). y″+25y=−40sin⁡(5t).

daser333 [38]

Answer:

Step-by-step explanation:

Non homogeneous differential

$y''+25y = -40sin(5t)---(1)$

To find homogeneous solution consider auxilary equation:

$D^{2}+25=0\\D=\pm5i$

Homogeneous solution is:

$y_{h}=Acos(5t)+Bsin(5t)\\$

Particular soution for -40 sin(5t)

$y_{p}= Csin(5t)+Dcos(5t)\\y'_{p}=5Ccos(5t)-5Dsin(5t)\\y''_{p}=-25Csin(5t)-25Dcos(5t)\\$

substituting value of $y_{p}, y''_{p}$ in (1)

$-25Csin(5t)-25Dcos(5t)+25Csin(5t)+25Dcos(5t)=-40sin(5t)\\\implies\\C=0\\D=0\\\implies \\y_{p}=0$

General solution is

$y=Acos(5t)+Bsin(5t)$

4 0

3 years ago

A student's course grade is based on one midterm that counts as 5% of his final grade, one class project that counts as 10% of h

LiRa [457]

Answer:

<u>The student's final score is 77.2 and he earned a C letter grade</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the math problem correctly:

Midterm = 5% of the final grade and score of 60

Class project = 10% of the final grade and score of 92

Set of homework = 35% of the final grade and score of 80

Final exam = 50% of the final grade and score of 74

2. What is the student's final score?

Final score = (60 * 0.05) + (92 * 0.1) + (80 * 0.35) + (74 * 0.5)

Final score = 3 + 9.2 + 28 + 37

Final score = 77.2 and letter grade of C

6 0

3 years ago

After buying supplies ruby had $32 left over she spent $4 on notebooks $18 on a backpack and $30 on a new calculator how much mo

elena-s [515]

Answer:

$84

Ruby started with $84 before purchasing the school supplies.

Step-by-step explanation:

$32 + $4 + $18 + $30 = $84

6 0

3 years ago

(04.03) The graph shows the amount of money paid when purchasing bags of caramel corn at the zoo:

Minchanka [31]

Answer:

Step-by-step explanation:

k= y/x

k= 3/1

k= 3

3x2= 6

3x3= 9

5 0

3 years ago

Read 2 more answers

Select the two values of x that are roots of this equation.<br> X2 + 2x - 5 = 0

LenaWriter [7]

Answer:

$x=-1+\sqrt{6 }$

$x=-1-\sqrt{6 }$

Step-by-step explanation:

$x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

Ignore the A before the ±. It wouldn't let me type it correctly.

x² + 2x - 5 = 0

a = 1

b = 2

c = - 5

$x=\frac{-2±\sqrt{2^{2}-4((1)(-5)) } }{2(1)}$

$x=\frac{-2±\sqrt{4-4((1)(-5)) } }{2(1)}$

$x=\frac{-2±\sqrt{4+20 } }{2(1)}$

$x=\frac{-2±\sqrt{24 } }{2}$

$x=\frac{-2±\sqrt{(2)(12) } }{2}$

$x=\frac{-2±\sqrt{(2)(2)(6) } }{2}$

$x=\frac{-2±\sqrt{(2)(2)(2)(3) } }{2}$

$x=\frac{-2±(\sqrt{2} )(\sqrt{2})(\sqrt{(2)(3) )} }{2}$

$x=\frac{-2±2\sqrt{6 } }{2}$

Two separate equations

$x=\frac{-2+2\sqrt{6 } }{2}$

$x=\frac{-2-2\sqrt{6 } }{2}$

$x=-1+\sqrt{6 }$

$x=-1-\sqrt{6 }$

7 0

3 years ago