2 years ago

Decide whether each equation is true for all, one, or no values of x.

Mathematics

1 answer:

Alina [70]2 years ago

4 0

Answer:

Step-by-step explanation:

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See explanation

Step-by-step explanation:

The given trigonometric equation is $cos(90-x)=-\frac{\sqrt{3} }{3}$ .

We take the inverse cosine of both sides to get:

$90-x=cos^{-1}(-\frac{\sqrt{3} }{3})$

$90-x=125$

$x=125-90$

$x=-35\degree=325\degree$ to the nearest degree

None of the options satisfies the given equation.

But if the question is actually;

$cos(90-x)=-\frac{\sqrt{3} }{2}$

Then;

$90-x=\cos^{-1}(-\frac{\sqrt{3} }{2})$ .

$90-x=210$ .

$x=-120\degree$ .

$x=360-120=240\degree$ .

In this case the answer will be B

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Decide whether each equation is true for all, one, or no values of x.​

Decide whether each equation is true for all, one, or no values of x.