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2 years ago

ANSWER THIS ASAP PLS Which of the following must be true if ABD = CDB?

Mathematics

1 answer:

Romashka [77]2 years ago

4 0

Answer:

option d. Both A and B must be true.

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Jocelyn purchased a new car in 2000 for $16, 100. The value of the car has

Maslowich

I think its 900 i’m not sure

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2 years ago

I need a long essay about may the bridges i burn light the way

aivan3 [116]

Answer:

I will let it lead me down the paths ahead of me. I never in my life thought that Dylan McKay would be a major influence on my growth as a person. But that's the way it seems to be going right now. So wish me luck, and may the bridges I've burned light the way.

this is not that long but I tried

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2 years ago

Use the drop down menus to correctly complete the statement.

Lubov Fominskaja [6]

If the diagonals of a quadrilateral bisect all the angles, then it's a rhombus, converse of a property. If the diagonals of a quadrilateral are perpendicular bisectors of each other, then it's a rhombus, converse of a property.

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2 years ago

) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection

RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

$C_{(m,n)} = \frac{m!}{n!(m-n)!}$

In this question, m = 18, n = 9. So the total number of possibilities is:

$T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620$

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

$D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715$

The probability is the number of desired possibilities divided by the number of total possibilities. So

$P = \frac{715}{48620} = 0.015 = 1.5%$

The probability the he or she will answer correctly is 1.5%

3 0

3 years ago

Solve for x and y <br> 8x-2y=24

TiliK225 [7]

Answer: For y it's y=4x−12 and for x it's x=12+y/4

Step-by-step explanation:

SOLVING FOR X

8x-2y=24

2(4x−y)=24

4x−y=24/2

4x−y=12

4x=12+y

x=12+y/4

SOLVING FOR Y

8x-2y=24

2(4x−y)=24

4x−y=24/2

4x−y=12

−y=12−4x

y=−12+4x

y=4x−12

Hope this helps, have a BLESSED AND WONDERFUL DAY! As well as a great Black History Month and Valentine's day! :-)

- Cutiepatutie ☺❀❤

8 0

2 years ago