Answer:
This is your work so i cant do it but I can give you a hint divide both the numerator and deomonator to get simplified form
Step-by-step explanation:
Question 1:
For that point where all the lines intersect to be an incenter, the following must be true
4x - 1 = 6x - 5
Subtract both sides by 6x
-2x -1 = -5
Add both sides by 1
-2x = -4
Divide both sides by -2
x= 2
Question 2:
Plug in x=2 into any of the two equations.
You get 7.
Have an awesome day! :)
This is how I would work it out:
1st no. = x+1 2x+10=3(x+1)-7
2nd no. = x 2x+10=3x-4
x=14
1st no. is 15; 2nd no. is 14
To check: 28+10=38; three times the larger is 45; and 38 is 7 less than 45.
Is this what you mean this is what i understood.
X-4=10;4x+1=57
First equation solve for x.
X-4=10
Add 4 both sides
X=10+4
X=14
Second equation substitute your x answer into second equation to make both sides equal.
4x+1=57
4(14)+1=57
56+1=57
57=57
Answer:
IQR = 22
Step-by-step explanation:
IQR Formula:
IQR = Q3 - Q1
In order you find Q3 and Q1, please follow these steps:
1. First, you need to order the list of numbers from least to greatest:
2, 6, 9, 10, 16, 28, 33
2. Then, you need to find the median, or the middle number.
2, 6, 9, 10, 16, 28, 33
3. In order to find IQR, you must find the first and third quartiles.
2, 6, 9, 10, 16, 28, 33
Q1 = 6
Q3 = 28
This is because 6 basically means that all the numbers leading to 6 would account for 25% of the data while all the numbers leading to 28 would account for 75% of the data, hence why these are called quartiles.
Now since you have Q1 and Q3, you follow the formula.
28 - 6 = 22
IQR = 22
