Answer:
Step-by-step explanation:
Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...
We know from the given points that we can write the equation as ...
Comparing this to the desired form, we see that ...
So, the approximate equation for P is ...
And the parameters of interest are ...
Answer:100 + 3.2t = b
Step-by-step explanation: first off i would organize the data then find the varible(s) after you have all of the data organized with the verible(s) then find what number the varibles belong to. after that is done you would make
the equation which should look like 100 + 3.2t = b
If you see that 3x-3 and set it equal to x+7 then you will get this,
3x-3=x+7
Now solve for X. You will get 5.
Then you plug five in and get 12 For both sides and then multiply 12 by 4 and get 48.
You answer is 48.
Hope this helps you.
Answer:
See explanation and hopefully it answers your question.
Basically because the expression has a hole at x=3.
Step-by-step explanation:
Let h(x)=( x^2-k ) / ( hx-15 )
This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.
Solving for x in that equation:
Adding 15 on both sides:
hx=15
Dividing both sides by h:
x=15/h
For it be a hole, you also must have the numerator is zero at x=15/h.
x^2-k=0 at x=15/h gives:
(15/h)^2-k=0
225/h^2-k=0
k=225/h^2
So if we wanted to evaluate the following limit:
Lim x->15/h ( x^2-k ) / ( hx-15 )
Or
Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.
We were ask to evaluate
Lim x->3 ( x^2-k ) / ( hx-15 )
Comparing the two limits h=5 and k=225/h^2=225/25=9.
The best way to approach this problem is to look at the graph of the given function. Replace values of x from 1 to 24 to indicate the numbers of hours in a day. As seen on the graph, there is only one point where the port is at high tide. That would be at 1:00 am.
Looking at the graph, it would be safe for the boats to be in the port when the graph levels off at around 10 to 24. That's from 10 am to before 12 midnight. Then, they would have to stay away between 12 midnight to before 10 am.