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icang [17]
3 years ago
14

Can you see the specific pattern they follow?(2,4,6,8...)(3,6,12,24...)( 5,10,15,20,...)​

Mathematics
1 answer:
mars1129 [50]3 years ago
8 0
They times each number by 2
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Determine if the graph is a function then state the domain and range.
nignag [31]
<h3><u>Explanation</u></h3>

A function is a set of relation that doesn't have repetitive domain. If we want to know if a graph is function or not, we have to do the line test.

<u>Line</u><u> </u><u>Test</u>

  1. Draw a vertical line. Make sure that a line passes through a graph.
  2. See if a line intercepts a graph more than one point or just only one.

<u>Result</u>

If a line intercepts a graph more than one point, it is not a function.

However, if a line only intercepts a graph just one point, it is indeed a function.

The given graph from the question is a function because it passes line test.

<u>Domain</u><u> </u><u>and</u><u> </u><u>Range</u>

Domain is the set of all x-values, meaning we only focus on x-axis or x-value only.

Range is the set of all y-values. We only focus on y-value or y-axis for Range.

<u>Determine</u><u> </u><u>Domain</u><u> </u><u>from</u><u> </u><u>Graph</u>

We can simply say that the domain is from starting domain or x-coordinate point to end x-coordinate point. For example, if a graph starts at x = -4 and ends at x = 2, we can say that - 4<=x=2.

<u>Determine</u><u> </u><u>Range</u><u> </u><u>from</u><u> </u><u>Graph</u>

Similar to Domain except Range starts from the minimum value or point to the maximum point or value. For example if a graph starts at min point = 6 and max point = 9. We can say that 6<=y<=9.

From the graph, the domain starts from negative infinity to positive infinity. Meaning that x can be any numbers. Hence, the domain is set of all real numbers. For range, the minimum value is 0 and max value is positive infinity. Therefore we write y>=0.

<h3><u>Answer</u></h3>

<u>\begin{cases} x \in  \mathbb{R} \\ y \geqslant 0 \end{cases}</u>

<u>Domain</u><u> </u><u>is</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>all</u><u> </u><u>real</u><u> </u><u>numbers</u><u>.</u>

<u>Range</u><u> </u><u>is</u><u> </u><u>greater</u><u> </u><u>or</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>0</u><u>.</u>

8 0
3 years ago
A landscaper is selecting two trees to plant. He has five to choose from. Three of the five are deciduous and two are evergreen.
ICE Princess25 [194]

Answer:

The probability that he chooses trees of two different types is 30%.

Step-by-step explanation:

Given that a landscaper is selecting two trees to plant, and he has five to choose from, of which three of the five are deciduous and two are evergreen, to determine what is the probability that he chooses trees of two different types must be performed the following calculation:

3/5 x 2/4 = 0.3

2/5 x 3/4 = 0.3

Therefore, the probability that he chooses trees of two different types is 30%.

4 0
3 years ago
Read 2 more answers
Round 496179.784414 to the nearest thousand
FrozenT [24]

Answer:

the answer is going to be 496,000. If you meant "Thousandth" and not "Thousand" the answer is going to be 496,179.784


6 0
4 years ago
Read 2 more answers
Ok ok this i need help
lakkis [162]

Answer:

2

Step-by-step explanation:

18-4^2=2

7 0
3 years ago
Read 2 more answers
Can someone help me and explain? I will mark brainlest. ♡
Sedbober [7]

Answer:

p'(4) = -3

q'(8) = \frac{1}{4}\\

Step-by-step explanation:

For p'(4):

p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)

p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3

For q'(8):

q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}

q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}

4 0
4 years ago
Read 2 more answers
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