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GenaCL600 [577]
3 years ago
15

Find the like terms.Please help..Please...3x-2y-3x

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

The like terms would be 3x and -3x.

Step-by-step explanation:

If you add the like terms together you would get 0x and be left with -2y.

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Ms. Abrams receives a 4% commission plus a salary of $275.00 per week. If her total sales for one week are $2,880.00, how much d
Marta_Voda [28]
390.20 is the answer because 4%of 2880 is 115.20 plus 275.00 is 390.20
8 0
3 years ago
This is Anya's solution for the equation x ^ 2 - 6x - 7 = 0 Is her solution correct ? Explain your answer in detail points ANSWE
tia_tia [17]

Answer:

Anya is incorrect.

Step-by-step explanation:

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The correct answer is x = −1 or x = 7

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5 0
3 years ago
Read 2 more answers
Go to Canvas to watch an instructional video and complete the assignment. After watching the video and uploading the assignment
Reptile [31]

This is simply what I wrote for my assignment, sorry I am a bit late.

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7 0
3 years ago
2/3 as afraction with a denominator of 6
yanalaym [24]

Answer:

4/6

Step-by-step explanation:

3 x 2 = 6

2 x 2 = 4

2/3 = 4/6

6 0
3 years ago
What is the vertex of the parabola whose equation is y = (x + 1)2 + 3? (-1, -3) (-1, 3) (1, 3)
White raven [17]
Algebra:
A standard parabola is y = x^2. Its vertex is at (0,0)
You can change the position (or vertex) of the parabola.
To move a parabola across the x-axis, you can add or subtract a number from x WITHIN brackets of the ^2
eg. (x + 1)^2 will move the parabola across the x-axis. It will move is one unit to the LEFT (as the sign is opposite to the direction it moves ie. The sign it + but you move the whole parabola in the -ve direction).
Adding or subtracting a number from x OUTSIDE of the ^2 moves the parabola up or down the y-axis
eg. x^2 + 3 will move the parabola UP 3 units (the sign is the same as the direction it moves when the added/subtracted number is outside of the ^2 ie. the sign is positive so the parabola moves up in the positive direction)

From this, we can conclude that because (x + 1)^2 + 3, the vertex will be where x = -1 and where y = 3

Vertex : (-1,3)



Calculus:
f(x) = (x + 1)^2 + 3 = x^2 + 2x + 1 + 3 = x^2 + 2x + 4
Expanding the formular to make it easier to differentiate

f'(x) = 2x + 2
Differentiating (finding the formular the the gradiet of the parabola)

0 = 2x + 2
When the gradient is equal to zero, it must be the vertex

-2 = 2x
-2/2 = x
x = -1
Solve to give the x value at the vertex

f(x) = (x + 1)^2 + 3
= (-1 + 1)^2 + 3
Substitute x = -1 into original equatiom to find y value at the vertex

= (0)^2 + 3
= 0 + 3
= 3
Solve for y

Vertex : (-1,3)


6 0
3 years ago
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