Answer:
617 pickles left >:)
Step-by-step explanation:
1234 divided by 2(half) is 617
also fred is very hungry if he wanted 617 pickles...and greedy
Answer:
The equation is;
y = 12x-41
Step-by-step explanation:
Mathematically;
slope intercept form is;
y = mx + b
where m is slope and b is intercept
Since we already have the slope , the equation is;
y = 12x + b
To get b which is the y intercept, we simply substitute the value of the points given
Thus;
19 = 5(12) + b
19 = 60+ b
b = 19-60
b = -41
So the equation is;
y = 12x - 41
Hello!
The problem has asked that we write a
point-slope
equation of the line in the image above.
Point-Slope Form uses the following formula:
y –

= m(x –

)
In this case, M represents the
slope while

and

represent the
corresponding X and Y values of any given point on the line.
We are given that the slope of the line is -

. We also know that any given point on a graph takes the form (x,y). Based on the single point provided in the image above, we can determine that

is equal to
6 and

is equal to
2. Now insert all known values into the point-slope formula above:
y – 2 = -

(x – 6)
We have now successfully created an equation based on the information given in the problem above. Looking at the four possible options, we can now come to the conclusion that
the answer is C.
I hope this helps!
Answer:
100°
Step-by-step explanation:
A triangle is a polygon shape with three sides. Triangles are of different types such as obtuse, scalene, equilateral, isosceles etc.
In triangle ABC:
70° + 50° + ∠C = 180° (sum of angles in a triangle)
120 + ∠C = 180
∠C = 180 - 120
∠C = 60°
Since ∠C is bisected into ∠ACD and ∠BCD, hence:
∠ACD = ∠BCD = ∠C / 2
∠ACD = ∠BCD = 60 / 2
∠ACD = ∠BCD = 30°
In triangle ACD:
∠A + ∠ACD + ∠ADC = 180° (sum of angles in a triangle)
50 + 30 + ∠ADC = 180
∠ADC + 80 = 180
∠ADC = 100°
Answer:
B) 4√2
General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Parametric Differentiation
Integration
- Integrals
- Definite Integrals
- Integration Constant C
Arc Length Formula [Parametric]: ![\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20AL%20%3D%20%5Cint%5Climits%5Eb_a%20%7B%5Csqrt%7B%5Bx%27%28t%29%5D%5E2%20%2B%20%5By%28t%29%5D%5E2%7D%7D%20%5C%2C%20dx)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

Interval [0, π]
<u>Step 2: Find Arc Length</u>
- [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:

- Substitute in variables [Arc Length Formula - Parametric]:
![\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20AL%20%3D%20%5Cint%5Climits%5E%7B%5Cpi%7D_0%20%7B%5Csqrt%7B%5B1%20%2B%20sin%28t%29%5D%5E2%20%2B%20%5B-cos%28t%29%5D%5E2%7D%7D%20%5C%2C%20dx)
- [Integrand] Simplify:
![\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20AL%20%3D%20%5Cint%5Climits%5E%7B%5Cpi%7D_0%20%7B%5Csqrt%7B2%5Bsin%28x%29%20%2B%201%5D%7D%20%5C%2C%20dx)
- [Integral] Evaluate:
![\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20AL%20%3D%20%5Cint%5Climits%5E%7B%5Cpi%7D_0%20%7B%5Csqrt%7B2%5Bsin%28x%29%20%2B%201%5D%7D%20%5C%2C%20dx%20%3D%204%5Csqrt%7B2%7D)
Topic: AP Calculus BC (Calculus I + II)
Unit: Parametric Integration
Book: College Calculus 10e