Multiplying both sides of the equation by 3 and substituting 4 for p
25(cards per month) x12(months in one year) =300 cards at the end of one whole year
Answer:
3(15+12)
Step-by-step explanation:
3(5+4)
3( 5 x 3 =15 and 4 x 3= 12)
Answer:
1)Area; A = ¼πr²
Perimeter; P = πr/2 + 2r
2)A = 19.63 cm²
P = 17.85 cm
3) r = 8.885 cm
4) r = 14 cm
Step-by-step explanation:
This is a quadrant of a circle. Thus;
Area of a circle is πr². A quadrant is a quarter of a circle. Thus;
Formula for Quadrant Area is; A = ¼πr²
A) Perimeter of a circle is 2πr. Thus, perimeter of a quadrant is a quarter of the full circle perimeter.
Formula for the quadrant perimeter in the image given is;
P = 2πr/4 + 2r
P = πr/2 + 2r
B) When r is 5 cm;
A = ¼π(5)²
A = 19.63 cm²
P = π(5)/2 + 2(5)
P = 17.85 cm
C) when A is 100cm²:
¼πr² = 100
r² = 100 × 4/π
r² = 78.9358
r = √78.9358
r = 8.885 cm
D) when P = 50 cm.
50 = πr/2 + 2r
50 = (½π + 2)r
r = 50/(½π + 2)
r = 14 cm
Answer:
Composite Area = 1105.94
Step-by-step explanation:
Remark
The two semi circles at each end make an entire circle with radius 11. The width of the central rectangle = the diameter of the circle. The area should be able to be found.
Width
2*radius = width
width = 2 * 11
width = 22
Area of the circle
Area = pi * r^2
r = 11
Area = 3.14 * 11^2
Area = 3.14 * 121
Area = 379.94
Area of the rectangle
Area = L * W
L = 33
W = 22
Area = 33 * 22
Area = 726
Total Area
Total Area = Area of Rectangle + Area of the Circle
Total Area = 726 + 379.94 = 1105.94
