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3 years ago

A card is drawn at random from a standard pack of 52 playing cards find the probity of drawing a heart or a club

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

5 0

Answer:

1/2

Step-by-step explanation:

From the question, there are 13 cards of heart and 13 card of club in each suit in each deck.

P(drawing heart) = 13/52

P(drawing club) = 13/52

And we know total standard pack =52

P(drawing a heart or a club)

= number of favourable outcome/ total Number of outcome

P( drawing heart or club) =( 13+13)/52

=26/52

=1/2

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Find the midpoint of the segment with the following endpoints. (2,9) and (8,1)

vazorg [7]

Answer:

$\displaystyle (5,5)$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Midpoint Formula: $\displaystyle (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define

Point (2, 9)

Point (8, 1)

Step 2: Identify

(2, 9) → x₁ = 2, y₁ = 9

(8, 1) → x₂ = 8, y₂ = 1

Step 3: Find Midpoint

Simply plug in your coordinates into the midpoint formula to find midpoint

Substitute in points [Midpoint Formula]: $\displaystyle (\frac{2+8}{2},\frac{9+1}{2})$
[Fractions] Add: $\displaystyle (\frac{10}{2},\frac{10}{2})$
[Fractions] Divide: $\displaystyle (5,5)$

7 0

3 years ago

The question is in the picture

otez555 [7]

Answer:

x=27.8

Step-by-step explanation:

first, you need to find y. 2y-5=65. 65+5 is 60 and you are left with 2y=70. to get the 2 off of the y you divide everything by 2. 70/2 is 35 therefor y=35. Now you plug that into the other equation (2x+y) and get 2x+35 which is equal to segment 90.6 so 2x+35=90.6. subtract 35 on both sides and you have 2x=55.6. To get the 2 off the x, we divide everything by 2. all of that divided by 2 is x=27.8

5 0

2 years ago

For the function f(x) = 7/2x-16, what is the difference quotient for all nonzero values of h?

sergey [27]

Answer:

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}$