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IceJOKER [234]
3 years ago
5

Frank reasoned that in the number 0.555, the value of the 5 in the thousands place is ten times as great as the 5 in the hundred

ths place. Is he correct?
Mathematics
1 answer:
taurus [48]3 years ago
6 0
Yes bro hope it helped give me a thanks
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Adi used algebra tiles to represent the product (negative 2 x minus 1)(2 x minus 1). An algebra tile configuration. 4 tiles are
Hunter-Best [27]

Answer:

Step-by-step explanation:

c

8 0
3 years ago
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Simone used 2 1/3 kilograms of flour to bake a cake . She used 4/5 kilograms of flour more to bake a second cake. How much flour
Likurg_2 [28]

Answer:

3.13 kilograms used for the second cake

Step-by-step explanation:

because the fractions have different denominators you have to multiply the denominators together to figure out what to change them too. but instead you can just figure out what the decimal for each is. 1/3 is 0.33, and 4/5 is 0.80. all you do is add these together to get 1.13. so now all you do is add 2+1.13 to get 3.13.

5 0
3 years ago
PLEASE HELP IF THE ANSWER DOES NOT APPLY TO THIS I WILL REPORT
tensa zangetsu [6.8K]
0.63 is the correct answer
4 0
3 years ago
Help me with these problems please
Scorpion4ik [409]
1. y = 7
2. 0
3. m = -1
4. k = -4
5. x = -6
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7 0
3 years ago
Solve for
faust18 [17]

Given equation : n(17+x)=34x−r.

We need to solve it for x.

Distributing n over (17+x) on left side, we get

17n + nx  = 34x - r.

Adding r on both sides, we get

17n+r + nx  = 34x - r+r.

17n + r + nx = 34x.

Subtracting nx from both sides, we get

17n + r + nx-nx = 34x-nx

17n + r = 34x -nx.

Factoring out gcf x on right side, we get

17x + r = x(34-n).

Dividing both sides by (34-n), we get

\frac{(17x + r)}{(34-n)} = \frac{x(34-n)}{(34-n)}

\frac{(17x + r)}{(34-n)} = x

<h3>Therefore, final answer is x=\frac{(17x + r)}{(34-n)}.</h3>
7 0
3 years ago
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