Answer:
YES
Step-by-step explanation:
-(x-10)=7
-x+10=7
-x=7-10
-x=-3
x=3
-12p-20
{-12-6p-(-2)}−12−6p−(−2)
-12-6p+2−12−6p+2
These three roots are sufficient to enable us to form a 3rd degree polynomial:
f(x) = (x+4)(x-4)(x-2) = (x^2 - 16)(x-2) = x^3 - 2x^2 - 16x + 32 (answer)
