The best way to think about this value is to picture the graph of the "normal" sin wave. One period starts at (0, 0), goes up to a y value of 1 at an x value of 
, goes back down to a y value of 0 at x = 
, goes down to a y value of -1 at x = 
and ends up completing one period at a y value of 0 and an x value of 
. We can see from that what the sin ratios are at each one of those x values. When x = 0, y = 0, so the sin of 0 is 0. Check your calculator to see that this is true, but understanding the graph tells you WHY it is true.
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Answer:
Following are the solution to the given equation:
Step-by-step explanation:
The graph file and correct question are defined in the attachment please find it.
According to the linear programming principle, we predict, that towards the intersections of the constraint points in the viability area, and its optimal solution exists. The sketch shows the points that are (0,16), (3,1), and (6,0).
by putting each point value into the objective function:
Thus, the objective of the function is reduced with a value of 183 at (3,1).
