Answer:
1
Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
2
+
5
−
2
=
0
x^{2}+5x-2=0
x2+5x−2=0
=
1
a={\color{#c92786}{1}}
a=1
=
5
b={\color{#e8710a}{5}}
b=5
=
−
2
c={\color{#129eaf}{-2}}
c=−2
=
−
5
±
5
2
−
4
⋅
1
(
−
2
)
√
2
⋅
1
Step-by-step explanation:
this should help
Answer: (3)12 + 6x = 84
Step-by-step explanation:
We know he definitely bought 3 books for $12 each so we immediately put that in the equation. Then we add that to the unknown (6 books times however much he bought them for) and then we equal it to 84 (his budget). Now we do 3 x 12 which is 36. Our new equation is 36 + 6x = 84. 84 - 36 = 48 so we know 6x = 48. Now divide 48 by 6 to get rid of the 6 and we learn that the variable equals 8. So, x = 8. We now know that he bought 6 books at 8 dollars each.
520 CD's because of the 9 months and we add 30 time 9 we erase the 0 and multiply the 3 with the 9 it will be 27 right we add the zero because the originla number is 30
