Answer:
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Step-by-step explanation:
Tamira invests $5,000 in an account
Rate of interest = 4%
Time = 3 years
Case 1:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 1
Formula :

A=5624.32
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
Case 2:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 2
Formula : 

A=5630.812
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
Case 3:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula : 

A=5634.125
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
Case 4:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula :

A=5636.359
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Answer:
y=-1 : )
Step-by-step explanation:
(Brainliest Please)
Answer
4. - x ^ 2 + 13x - 42 <= 0524211r
5. x ^ 2 - 11x - 42 < 0
16 - x ^ 2 + 9x - 8 <= 0
17. x^ 2 -11x+80<0
18. - x ^ 2 + 3x + 4 <= 0
19. x ^ 2 - 12x + 36 <= 0
20. 2x ^ 2 - 32x + 56 < 0
21. x ^ 2 - 10x - 96 < 0
Since we have to solve the given formula for h(height) so, the correct option is (a)