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elena-s [515]
2 years ago
10

Jim did 35 push-ups on Saturday, 42 push-ups on Sunday, 49 push-ups on Monday, and 56 push-ups on Tuesday. What kind of sequence

is this?
Mathematics
1 answer:
just olya [345]2 years ago
8 0

Answer:

increasing sequence of +7

Step-by-step explanation:

please mark brainiest

please give 5 stars

thank you

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5=4b-12 hurry and make sure you put how you got the answer
PIT_PIT [208]

Answer:

4.25

Process:

  • 5=4b-12
  • 4b=12+5
  • 4b=17
  • b=\frac{17}{4}
  • b= 4.25
5 0
2 years ago
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pleaseee help context is down below $3 is the entrance fee while $.50 is for each game played that's enough evidence to solve C(
BabaBlast [244]
C= Cost
g= # of times games played

C = 0.50g + 3

C(0) = 0.50(0) + 3
C(0) = 0 + 3
C(0) = 3

This means that no games have been played yet and the entrance fee is $3
5 0
2 years ago
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Radio signals travel at a rate of 3x10^8 meters per second how many seconds would it take for a radio signal to travel from a sa
marshall27 [118]

Answer:

1.2x10^-1 seconds

Step-by-step explanation:

4 0
2 years ago
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Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
2 years ago
Is this a complementary, supplementary, vertical, or adjacent <br><br>ill give brainly​
WINSTONCH [101]

Answer:

its complemtary

Step-by-step explanation:

check this photo

6 0
2 years ago
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