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dolphi86 [110]
3 years ago
9

A rectangle has vertices at these coordinates (0,8),(5,8),(5,0) what are the coordinates of the fourth vertex of the rectangle

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
7 0
Answer: (0,0) hope this helps
Evgen [1.6K]3 years ago
3 0

Answer:

(0,0)

Step-by-step explanation:

On the other side of the rectangle, (5,0) is 8 units down from (5,8) so just go down 8 from (0,8) and you'll arrive at the origin, or (0,0).

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stepladder [879]

Answer:

20x + 20

Step-by-step explanation:

4(2x+3)+ 4(3x+2)

Expand the brackets.

8x + 12 + 12x + 8

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20x + 20

6 0
3 years ago
How would I do this?
Veseljchak [2.6K]

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Your equation is 180=90+28+x

8 0
3 years ago
Read 2 more answers
A. 12 <br> b. 14<br> c. 8<br> d. 6
jolli1 [7]

Answer:

  d.  6

Step-by-step explanation:

The product of lengths to the near and far intersection points is the same for both secants:

  PB×PA = PD×PC

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  7×12 = (3x)(7x)

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  2 = x . . . . . . . . . . take the square root

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5 0
3 years ago
5 units from ( negative 1, negative 2) what is the coordinate ( , negative 2) explain why
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The two negetive points of the block add thise to you answer
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3 years ago
Find the missing side lengths. Leave your answers as radicals in simplest form
tino4ka555 [31]

We have the triangle 30° - 60° - 90°.

The lenght of the sides are in proportion: 1:2:\sqrt3\to a:2a:a\sqrt3

a=y\\2a=x\\a\sqrt3=5\\\\a\sqrt3=5\qquad\text{multiply both sides by}\ \sqrt3\\\\3a=5\sqrt3\qquad\text{divide both sides by 3}\\\\a=\dfrac{5\sqrt3}{3}\\\\2a=2\cdot\dfrac{5\sqrt3}{3}=\dfrac{10\sqrt3}{3}\\\\Answer:\ x=\dfrac{10\sqrt3}{3},\ y=\dfrac{5\sqrt3}{3}

6 0
3 years ago
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