We know that:
Substituting known values, we have:
4a5+28+6b7-30
4a5+6b7-2<—- this is a to the power of 5 , b to the power of 7
(Is that 5a or a to the power of 5 )
20a+28+42b-30
20a+42b-2<—— this is 5a , 7b
The statements that aer true or not or whatever
hmm, let's try te sencnarios
remember the commutative property of multiplication
ab=ba
so
what if they are both negative?
well, the negatives would cancel to leave with positive
the oposite would be both positive resulting in a positive
if they are differnt signs then result is negative
oposite would be still different signs so still negative
true statment
<h3>
Answer: x3 +2 +x+x+</h3>
Step-by-step explanation:
Since the problem is to prove that the two triangles are congruent by applying SSS (side -side -side) congruence theorem, the missing or the additional information that can be shown in the solution is the third side of both triangles must be also equal and congruent. Since in SSS theorem, all sides of a given triangle must be congruent to the opposite three sides of the second triangle.
