-11+9= 5t
-2=5t (divide both sides by 5)
t= -2/5
(Mark me the brainliest if this has helped )
The common ratio between terms is 3, so the sequence has general
-th term
![a_n=3^{n-1}](https://tex.z-dn.net/?f=a_n%3D3%5E%7Bn-1%7D)
for
. The term exceeds 7000 when
![3^{n-1}>7000\implies n-1>\log_37000\implies n>1+\log_37000\approx9.06](https://tex.z-dn.net/?f=3%5E%7Bn-1%7D%3E7000%5Cimplies%20n-1%3E%5Clog_37000%5Cimplies%20n%3E1%2B%5Clog_37000%5Capprox9.06)
which means the first time
exceeds 7000 occurs when
. Indeed,
![a_{10}=3^{10-1}=19,683](https://tex.z-dn.net/?f=a_%7B10%7D%3D3%5E%7B10-1%7D%3D19%2C683)
while the previous term would have been
![a_9=3^{9-1}=6561](https://tex.z-dn.net/?f=a_9%3D3%5E%7B9-1%7D%3D6561)
Answer/Step-by-step explanation:
The equation of the line that passes through the two points would be correct if each point, when substituted into the equation, satisfy the equation.
This is what I mean:
Given the equation of the line, y = 2x - 5, and the two points (-2, -9) and (3, 1):
For the first point, substitute x = -2, and y = -9 into y = 2x - 5.
Thus:
-9 = 2(-2) - 5
-9 = -4 - 5
-9 = -9 (this is true). It means the line runs through the point (-2, -9)
For the second point, substitute x = 3, and y = 1 into y = 2x - 5
This:
1 = 2(3) - 5
1 = 6 - 5
1 = 1 (this is true). This also means the point, (3, 1) is also a point that the equation runs across.
The method used is Distributive Property.
<h3>What is Distributive property?</h3>
The Distributive Property is an algebraic property that is used to multiply a single value and two or more values within a set of parenthesis.
Given:
(2x² - 1)(3x+2) = (2x²)(3x) + (2x²)(2) + (-1)(3x)+(-1)(2)
Here the property used is Distributive property.
Because distributive property in this way
a*(b+c)= a*b+ a*c
This is how a is being multiplied by with b and c.
Learn more about this Distributive property here:
brainly.com/question/4136433
#SPJ1
Answer:
![(5,1)](https://tex.z-dn.net/?f=%285%2C1%29)
Step-by-step explanation:
Hi there!
Midpoint =
where the two endpoints are
and ![(x_2,y_2)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29)
Plug in the given information:
Midpoint = (5,3), Endpoint = (5,5)
where
is the other endpoint
Solve for
:
![\displaystyle \frac{5+x_2}{2} =5\\\\5+x_2 =10\\x_2 =5](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B5%2Bx_2%7D%7B2%7D%20%3D5%5C%5C%5C%5C5%2Bx_2%20%3D10%5C%5Cx_2%20%3D5)
Solve for
:
![\displaystyle\frac{5+y_2}{2}=3 \\\\{5+y_2}=6\\y_2=1](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B5%2By_2%7D%7B2%7D%3D3%20%5C%5C%5C%5C%7B5%2By_2%7D%3D6%5C%5Cy_2%3D1)
Therefore, the other endpoint
is
.
I hope this helps!